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Question 6

An isotope of argon, 1837Ar{}^{37}_{18}\text{Ar}1837​Ar, decays into an isotope of chlorine (Cl) by electron capture.

1.

Complete the equation for this decay by filling in the blanks:

1837Ar+−10e→‾Cl+‾ {}^{37}_{18}\text{Ar} + {}^{0}_{-1}\text{e} \rightarrow \underline{\quad}\text{Cl} + \underline{\quad} 1837​Ar+−10​e→​Cl+​
[2]
2.

Name the fundamental interaction responsible for this decay, identify its exchange boson, and explain why this interaction is uniquely capable of causing this change.

[3]
3.

After the decay, the chlorine nucleus is in an excited state. It returns to its ground state by emitting a single gamma photon with an energy of 0.320 MeV0.320 \text{ MeV}0.320 MeV. Calculate the wavelength of this photon.

[3]
4.

Another isotope, argon-39 (1839Ar{}^{39}_{18}\text{Ar}1839​Ar), decays by a different process to form potassium-39 (1939K{}^{39}_{19}\text{K}1939​K). Suggest what particles are emitted in this second process and explain how they could be detected and distinguished from the products of electron capture decay.

[3]

Particles Questions

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