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Question 15
Easy

The process of beta minus (β−\beta^-β−) decay can be represented by the Feynman diagram below.

Feynman diagram for beta minus decay. A straight line labeled 'n' enters from the bottom-left and meets at a vertex. From this vertex, a straight line labeled 'p' exits towards the top-left. From this first vertex, a wavy line representing an exchange particle labeled 'X' goes to a second vertex on the right. From this second vertex, two straight lines exit: one labeled 'Y' pointing towards the top-right, and another labeled 'beta minus' pointing towards the right.

Which row in the table correctly identifies particles XXX and YYY?

X=W−X = W^-X=W−, Y=νeY = \nu_{\text{e}}Y=νe​

X=W−X = W^-X=W−, Y=νˉeY = \bar{\nu}_{\text{e}}Y=νˉe​

X=W+X = W^+X=W+, Y=νeY = \nu_{\text{e}}Y=νe​

X=W+X = W^+X=W+, Y=νˉeY = \bar{\nu}_{\text{e}}Y=νˉe​

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