A reconnaissance satellite orbits Mars in a circular path at an altitude equal to the mean radius of Mars, RMR_MRM.
Mass of Mars, M=6.42×1023 kg \text{Mass of Mars, } M = 6.42 \times 10^{23} \text{ kg} Mass of Mars, M=6.42×1023 kg Mean radius of Mars, RM=3.39×106 m \text{Mean radius of Mars, } R_M = 3.39 \times 10^6 \text{ m} Mean radius of Mars, RM=3.39×106 m Gravitational constant, G=6.67×10−11 N m2 kg−2 \text{Gravitational constant, } G = 6.67 \times 10^{-11} \text{ N m}^2 \text{ kg}^{-2} Gravitational constant, G=6.67×10−11 N m2 kg−2What is the angular speed of the satellite in this orbit?
1.0×10−3 rad s−11.0 \times 10^{-3} \text{ rad s}^{-1}1.0×10−3 rad s−1
7.4×10−4 rad s−17.4 \times 10^{-4} \text{ rad s}^{-1}7.4×10−4 rad s−1
3.7×10−4 rad s−13.7 \times 10^{-4} \text{ rad s}^{-1}3.7×10−4 rad s−1
1.4×10−7 rad s−11.4 \times 10^{-7} \text{ rad s}^{-1}1.4×10−7 rad s−1