A satellite is in a semi-synchronous circular orbit around the Earth. The orbital period of the satellite is exactly 12 hours. What is the angular speed of the satellite?
7.3×10−5 rad s−17.3 \times 10^{-5} \text{ rad s}^{-1}7.3×10−5 rad s−1
1.5×10−4 rad s−11.5 \times 10^{-4} \text{ rad s}^{-1}1.5×10−4 rad s−1
2.9×10−4 rad s−12.9 \times 10^{-4} \text{ rad s}^{-1}2.9×10−4 rad s−1
8.7×10−3 rad s−18.7 \times 10^{-3} \text{ rad s}^{-1}8.7×10−3 rad s−1