Use the identity cos2θ+sin2θ≡1\cos^2\theta + \sin^2\theta \equiv 1cos2θ+sin2θ≡1 to prove that tan2θ≡sec2θ−1\tan^2\theta \equiv \sec^2\theta - 1tan2θ≡sec2θ−1.
Solve, for 0°≤θ≤360°0° \leq \theta \leq 360°0°≤θ≤360°, the equation
tan2θ+sec2θ+5secθ=2\tan^2\theta + \sec^2\theta + 5\sec\theta = 2tan2θ+sec2θ+5secθ=2
Give your answers to one decimal place.
225 exam-style questions on WJEC A Level Maths 3.5 Trigonometry (A-level only), covering 3.5.1 Trigonometry (A-level only), 3.5.2 Trigonometry (A-level only), 3.5.3 Trigonometry (A-level only), 3.5.4 Trigonometry (A-level only), 3.5.5 Trigonometry (A-level only), 3.5.6 Trigonometry (A-level only), 3.5.7 Trigonometry (A-level only), and 3.5.8 Trigonometry (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.