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3.5 Trigonometry (A-level only)

3.5 Trigonometry (A-level only)

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Question 106

The temperature, θ\thetaθ °C, inside a warehouse is modelled by the equation

θ=8+2sin⁡(15t−160)°+3cos⁡(15t−160)°\theta = 8 + 2\sin(15t - 160)° + 3\cos(15t - 160)°θ=8+2sin(15t−160)°+3cos(15t−160)°

where t t\,t is the number of hours after midnight.

a.

Express 2sin⁡x+3cos⁡x2\sin x + 3\cos x2sinx+3cosx in the form Rsin⁡(x+α)R\sin(x + \alpha)Rsin(x+α), where R>0 R > 0\,R>0 and 0°<α<90°0° < \alpha < 90°0°<α<90°. Give R R\,R to three significant figures and α \alpha\,α to two decimal places.

[3]
b.

Deduce the maximum temperature inside the warehouse during the day.

[1]
c.

Find the time of day at which this maximum temperature occurs, giving your answer to the nearest minute.

[3]
Markscheme

3.5 Trigonometry (A-level only) Questions

  1. A Level
  2. /Maths
  3. /3.5 Trigonometry (A-level only)

225 exam-style questions on WJEC A Level Maths 3.5 Trigonometry (A-level only), covering 3.5.1 Trigonometry (A-level only), 3.5.2 Trigonometry (A-level only), 3.5.3 Trigonometry (A-level only), 3.5.4 Trigonometry (A-level only), 3.5.5 Trigonometry (A-level only), 3.5.6 Trigonometry (A-level only), 3.5.7 Trigonometry (A-level only), and 3.5.8 Trigonometry (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.

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