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4.8 Kinematics (A-level only)

4.8 Kinematics (A-level only)

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Question 80

At time t t\,t seconds, where t≥0t \ge 0t≥0, a particle P P\,P has acceleration a=[(3t−3)i+(2t−4)j]\mathbf{a} = \left[(3t - 3)\mathbf{i} + (2t - 4)\mathbf{j}\right]a=[(3t−3)i+(2t−4)j] m s−2^{-2}−2.

Initially P P\,P has velocity (−4i+4j)(-4\mathbf{i} + 4\mathbf{j})(−4i+4j) m s−1^{-1}−1.

a.

Find an expression for the velocity of P P\,P in terms of ttt.

[3]
b.

Find the velocity of P P\,P at each of the two times when P P\,P is moving parallel to the vector (2i+j)(2\mathbf{i} + \mathbf{j})(2i+j).

[4]
Markscheme

4.8 Kinematics (A-level only) Questions

  1. A Level
  2. /Maths
  3. /4.8 Kinematics (A-level only)

163 exam-style questions on WJEC A Level Maths 4.8 Kinematics (A-level only), covering 4.8.1 Kinematics (A-level only), 4.8.2 Kinematics (A-level only), and 4.8.3 Kinematics (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.

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