At time t t\,t seconds, where t≥0t \ge 0t≥0, a particle P P\,P moves so that its acceleration is a=[(1−2t)i+(5−t2)j]\mathbf{a} = \left[(1 - 2t)\mathbf{i} + (5 - t^2)\mathbf{j}\right]a=[(1−2t)i+(5−t2)j] m s−2^{-2}−2.
At the instant when t=0t = 0t=0, the velocity of P P\,P is 20i20\mathbf{i}20i m s−1^{-1}−1.
Find the velocity of P P\,P when t=4t = 4t=4.
Find the value of t t\,t at the instant when P P\,P is moving in a direction perpendicular to i\mathbf{i}i.
163 exam-style questions on WJEC A Level Maths 4.8 Kinematics (A-level only), covering 4.8.1 Kinematics (A-level only), 4.8.2 Kinematics (A-level only), and 4.8.3 Kinematics (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.