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4.8 Kinematics (A-level only)

4.8 Kinematics (A-level only)

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Question 13

At 08:00 ship X X\,X has position vector (4i+2j)(4\mathbf{i} + 2\mathbf{j})(4i+2j) km and moves with constant velocity (−2i+3j)(-2\mathbf{i} + 3\mathbf{j})(−2i+3j) km h−1\text{h}^{-1}h−1. Another ship Y Y\,Y has position vector (−i−4j)(-\mathbf{i} - 4\mathbf{j})(−i−4j) km and moves with constant velocity (3i+5j)(3\mathbf{i} + 5\mathbf{j})(3i+5j) km h−1\text{h}^{-1}h−1.

a.

Find the relative displacement of ship X X\,X from ship Y Y\,Y after t t\,t hours.

[6]
b.

Find the time when X X\,X is due west of YYY.

[2]
c.

Find the time, after 08:00, when the ships are exactly 229 \sqrt{229}\,229​ km apart.

[6]
Markscheme

4.8 Kinematics (A-level only) Questions

  1. A Level
  2. /Maths
  3. /4.8 Kinematics (A-level only)

163 exam-style questions on WJEC A Level Maths 4.8 Kinematics (A-level only), covering 4.8.1 Kinematics (A-level only), 4.8.2 Kinematics (A-level only), and 4.8.3 Kinematics (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.

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