In this question, use g=9.8 m s−2g = 9.8 \text{ m s}^{-2}g=9.8 m s−2.
A precision sensor module is dragged across a rough horizontal laboratory floor. A horizontal tension of magnitude FFF newtons is applied to the module by a robotic arm.
The module moves with a constant acceleration of 0.75 m s−20.75 \text{ m s}^{-2}0.75 m s−2.
The sensor module has a weight of 4.41 N4.41 \text{ N}4.41 N.
The only resistance to motion is the friction between the module and the floor.
The coefficient of friction between the module and the floor is 0.220.220.22.
Find FFF.
104 exam-style questions on WJEC A Level Maths 4.9 Forces and Newton's laws (A-level only), covering 4.9.1 Forces and Newton's laws (A-level only), 4.9.2 Forces and Newton's laws (A-level only), 4.9.3 Forces and Newton's laws (A-level only), 4.9.4 Forces and Newton's laws (A-level only), and 4.9.5 Forces and Newton's laws (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.