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Radians

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Question 36

During a lab experiment, the lateral displacement LLL (in cm) of a precision pendulum is recorded relative to its resting position for small angular displacements α\alphaα (in radians). The relationship is modeled by:

L(α)=14.2+25sin⁡(α5)+12tan⁡(α4) L(\alpha) = 14.2 + 25\sin\left(\frac{\alpha}{5}\right) + 12\tan\left(\frac{\alpha}{4}\right) L(α)=14.2+25sin(5α​)+12tan(4α​)

Show that for small values of α\alphaα, the graph of LLL can be approximated by a straight line, and determine the equation of this line.

[5]

Radians Questions

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