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Radians

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Question 24
a.

Show that, for small values of θ\thetaθ measured in radians,

3cos⁡2θ+sin⁡4θ−2tan⁡3θ≈A+Bθ+Cθ2 3 \cos 2\theta + \sin 4\theta - 2 \tan 3\theta \approx A + B\theta + C\theta^2 3cos2θ+sin4θ−2tan3θ≈A+Bθ+Cθ2

where AAA, BBB and CCC are constants to be found.

[4]
b.

Use your answer to part (a) to find an approximation for

3cos⁡0.12+sin⁡0.24−2tan⁡0.18 3 \cos 0.12 + \sin 0.24 - 2 \tan 0.18 3cos0.12+sin0.24−2tan0.18

Give your answer to three decimal places.

[3]

Radians Questions

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