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3.2 Kinematics

3.2 Kinematics

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Question 167

A particle moves in a straight line with acceleration a=(3t+5) m s−2a=(3t+5)\text{ m s}^{-2}a=(3t+5) m s−2. At t=0t=0t=0 its velocity is 2 m s-1. At time t=Tt=Tt=T, its velocity is 6 m s-1.

a.

Show that 3T2+10T−8=03T^2+10T-8=03T2+10T−8=0.

[3]
b.

Determine TTT.

[2]
c.

Find the distance travelled between t=0t=0t=0 and t=Tt=Tt=T.

[3]
Markscheme

3.2 Kinematics Questions

  1. A Level
  2. /Maths
  3. /3.2 Kinematics

260 exam-style questions on OCR A Level Maths 3.2 Kinematics, covering 3.2.1 Language of kinematics, 3.2.2 Graphs in kinematics, 3.2.3 Displacement-time and velocity-time graphs, 3.2.4 Constant acceleration formulae, 3.2.5 Constant acceleration in two dimensions (A-level only), 3.2.6 Non-uniform acceleration in one dimension (A-level only), 3.2.7 Non-uniform acceleration in two dimensions (A-level only), 3.2.8 Motion under gravity using vectors (A-level only), and 3.2.9 Projectiles (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.

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