In this question use g=9.81 m s−2g = 9.81 \text{ m s}^{-2}g=9.81 m s−2.
A particle is projected from a point OOO with an initial speed uuu at an angle of 40∘40^\circ40∘ above the horizontal.
The particle lands at a point PPP which is 15 metres vertically below the level of OOO.
The particle takes 1.2 seconds to reach the maximum height of its trajectory.
Find the value of uuu.
Find the total time that the particle is in flight.
260 exam-style questions on OCR A Level Maths 3.2 Kinematics, covering 3.2.1 Language of kinematics, 3.2.2 Graphs in kinematics, 3.2.3 Displacement-time and velocity-time graphs, 3.2.4 Constant acceleration formulae, 3.2.5 Constant acceleration in two dimensions (A-level only), 3.2.6 Non-uniform acceleration in one dimension (A-level only), 3.2.7 Non-uniform acceleration in two dimensions (A-level only), 3.2.8 Motion under gravity using vectors (A-level only), and 3.2.9 Projectiles (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.