Skip to content
MathsGenie logo
Open app

Course home

  1. A Level
  2. Maths OCR
  3. Question bank

Conditional Probability

MediumHard
1234567891011121314151617181920212223242526272829303132333435363738394041424344454647484950515253545556575859606162636465666768697071727374757677787980818283848586878889909192939495969798
Question 86

A quality control engineer monitors a semiconductor fabrication process for two specific types of defects: alignment errors (EAE_AEA​) and bonding errors (EBE_BEB​).

Data from the production line indicates that:

P(EA∩EB)=0.15 P(E_A \cap E_B) = 0.15 P(EA​∩EB​)=0.15 P(EA′∩EB′)=0.25 P(E_A' \cap E_B') = 0.25 P(EA′​∩EB′​)=0.25 P(EB)=2P(EA) P(E_B) = 2P(E_A) P(EB​)=2P(EA​)
a.

Find P(EA)P(E_A)P(EA​).

[4]
b.

Calculate the conditional probability P(EB∣EA)P(E_B | E_A)P(EB​∣EA​).

[2]
c.

Determine if the events EAE_AEA​ and EBE_BEB​ are independent.

[1]

Conditional Probability Questions

  1. A Level
  2. /Maths
  3. /Conditional Probability