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Conditional Probability

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Question 44

The events X X\,X and Y Y\,Y are such that P(X)=0.8P(X) = 0.8P(X)=0.8, P(Y)=0.6P(Y) = 0.6P(Y)=0.6, and P(X∩Y)=0.5P(X \cap Y) = 0.5P(X∩Y)=0.5. Find

a.

P(X∪Y)P(X \cup Y)P(X∪Y)

[2]
b.

P(X∣Y)P(X|Y)P(X∣Y)

[3]
c.

P(X′∣Y′)P(X'|Y')P(X′∣Y′)

[3]

Conditional Probability Questions

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