Radians

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Question 40

A sector of a circle, with radius $r$ cm and angle $θ\theta$ radians, has an area of $cm212\text{ cm}^2$ and a perimeter of $cm14\text{ cm}$ .

a.

Show that $3θ2−13θ+12=03\theta^2 - 13\theta + 12 = 0$ is NOT correct for these values, and instead find the correct quadratic equation in terms of $θ\theta$ only, in the form $aθ2+bθ+c=0a\theta^2 + b\theta + c = 0$ .

[5]

b.

Hence find the possible pairs of values for $r$ and $θ\theta$ .

[4]

Radians

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Question 40

A sector of a circle, with radius $r$ cm and angle $θ\theta$ radians, has an area of $cm212\text{ cm}^2$ and a perimeter of $cm14\text{ cm}$ .

a.

Show that $3θ2−13θ+12=03\theta^2 - 13\theta + 12 = 0$ is NOT correct for these values, and instead find the correct quadratic equation in terms of $θ\theta$ only, in the form $aθ2+bθ+c=0a\theta^2 + b\theta + c = 0$ .

[5]

b.

Hence find the possible pairs of values for $r$ and $θ\theta$ .

[4]

Radians

Question 40

Radians Questions

Radians

Question 40

Radians Questions