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Question 38
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Solve the equation
2cos2x=12 2\cos^2 x = \frac{1}{2}
2
cos
2
x
=
2
1
for
0∘≤x≤360∘0^\circ \le x \le 360^\circ
0
∘
≤
x
≤
36
0
∘
.
[4]
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