f(x)=x5+3x2+x−10f(x) = x^5 + 3x^2 + x - 10f(x)=x5+3x2+x−10
Find f′(x)f'(x)f′(x)
The root of f(x)=0f(x) = 0f(x)=0 lies in the interval [1,1.5][1, 1.5][1,1.5].
Use the Newton-Raphson method, starting with x0=1.25x_0 = 1.25x0=1.25, to find the root of f(x)=0f(x) = 0f(x)=0 to 3 decimal places.
