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Further Kinematics

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Question 32

A boat B B\,B moves with a constant velocity. At noon, B B\,B is at the point with position vector (2i−5j) km(2\mathbf{i} - 5\mathbf{j}) \text{ km}(2i−5j) km with respect to a fixed origin OOO. At 1430 the boat is at the point with position vector (−8i+10j) km(-8\mathbf{i} + 10\mathbf{j}) \text{ km}(−8i+10j) km.

a.

Find the velocity of BBB.

[3]
b.

Find the bearing of the velocity vector

[2]
c.

Find an expression, in terms of ttt, for the position of BBB t t\,t hours after noon.

[2]

Further Kinematics Questions

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