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Further Kinematics

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Question 20

A ship S S\,S moves with a constant velocity. At 11:00, S S\,S is at the point with position vector (−4i+5j) km(-4\mathbf{i} + 5\mathbf{j}) \text{ km}(−4i+5j) km with respect to a fixed origin OOO. At 13:00, the ship is at the point with position vector (8i−1j) km(8\mathbf{i} - 1\mathbf{j}) \text{ km}(8i−1j) km.

a.

Find the velocity of SSS.

[2]
b.

Find the bearing of the velocity vector.

[2]
c.

Find an expression, in terms of ttt, for the position of SSS t t\,t hours after 11:00.

[2]

Further Kinematics Questions

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