The velocity of a particle after t t\,t seconds is given by v=(6t−2t2) m s−1v = (6t - 2t^2) \text{ m s}^{-1}v=(6t−2t2) m s−1.
Show that the acceleration of the particle is a=6−4ta = 6 - 4ta=6−4t
Hence find the time at which the acceleration of the particle is zero.
308 exam-style questions on Edexcel A Level Maths Variable Acceleration, covering 11.1 Functions of Time, 11.2 Using Differentiation, 11.3 Maxima and Minima Problems, 11.4 Using Integration, and 11.5 Constant Acceleration Formulae. Each one has a worked solution and a mark scheme showing where the marks go.