A particle P P\,P travels along a straight line such that at time t t\,t seconds, t≥0t \geq 0t≥0, after leaving the point O O\,O on the line, the velocity of PPP, v v\,v ms−1^{-1}−1, is modelled as
v=4t+6−2t2 v = 4t + 6 - 2t^2 v=4t+6−2t2Find the value of t t\,t at the point when P P\,P stops accelerating.
308 exam-style questions on Edexcel A Level Maths Variable Acceleration, covering 11.1 Functions of Time, 11.2 Using Differentiation, 11.3 Maxima and Minima Problems, 11.4 Using Integration, and 11.5 Constant Acceleration Formulae. Each one has a worked solution and a mark scheme showing where the marks go.