The velocity of a particle after t t\,t seconds is given by v=(6t−kt2) m s−1v = (6t - kt^2) \text{ m s}^{-1}v=(6t−kt2) m s−1, where k k\,k is a positive constant.
Find the time at which the acceleration of the particle is zero, giving your answer in terms of kkk.
308 exam-style questions on Edexcel A Level Maths Variable Acceleration, covering 11.1 Functions of Time, 11.2 Using Differentiation, 11.3 Maxima and Minima Problems, 11.4 Using Integration, and 11.5 Constant Acceleration Formulae. Each one has a worked solution and a mark scheme showing where the marks go.