The continuous random variable TTT is used to model the lifespan in hours, ttt, of a specific type of chemical reactant after it is activated.
The probability that the reactant lasts for more than ttt hours is given by P(T>t)=100(t+10)2,t≥0P(T > t) = \frac{100}{(t+10)^2}, \quad t \ge 0P(T>t)=(t+10)2100,t≥0
Show that the cumulative distribution function (CDF) of TTT is given by F(t)={1−100(t+10)2t≥00otherwiseF(t) = \begin{cases} 1 - \frac{100}{(t+10)^2} & t \ge 0 \\ 0 & \text{otherwise} \end{cases}F(t)={1−(t+10)21000t≥0otherwise
Find the probability that a randomly selected reactant will expire within 5 hours of activation.
Given that a reactant has already lasted for 5 hours, find the probability that it will last for at least 15 more hours.
Calculate the number of hours after which only 25%25\%25% of these reactants are expected to remain active.
Practise Edexcel A Level Maths Conditional Probability with exam-style questions for A Level Maths. 100 questions covering Set Notation, Conditional Probability, Conditional Probabilities in Venn Diagrams, Probability Formulae, and Tree Diagrams, matched to the Edexcel A Level Maths (9MA0) specification and written in Paper 1, Paper 2 and Paper 3 style. Every question includes a full worked solution and mark scheme, so you can see where marks are awarded rather than just whether you got the answer right.