The events A and B are such that P(A)=14\displaystyle P(A) = \frac{1}{4}P(A)=41, P(A∩B)=110\displaystyle P(A \cap B) = \frac{1}{10}P(A∩B)=101, P(A∣B)=25\displaystyle P(A|B) = \frac{2}{5}P(A∣B)=52. Find
P(B)P(B)P(B)
368 exam-style questions on Edexcel A Level Maths Conditional Probability, covering 2.1 Set Notation, 2.2 Conditional Probability, 2.3 Conditional Probabilities in Venn Diagrams, 2.4 Probability Formulae, and 2.5 Tree Diagrams. Each one has a worked solution and a mark scheme showing where the marks go.