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Conditional Probability

Conditional Probability

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Question 189

The events A and B are such that P(A)=15\displaystyle P(A) = \frac{1}{5}P(A)=51​, P(A∩B)=120\displaystyle P(A \cap B) = \frac{1}{20}P(A∩B)=201​, P(B)=310\displaystyle P(B) = \frac{3}{10}P(B)=103​. Find

P(A∪B)P(A \cup B)P(A∪B)

[3]
Markscheme

Conditional Probability Questions

  1. A Level
  2. /Maths
  3. /Conditional Probability

330 exam-style questions on Edexcel A Level Maths Conditional Probability, covering 2.1 Set Notation, 2.2 Conditional Probability, 2.3 Conditional Probabilities in Venn Diagrams, 2.4 Probability Formulae, and 2.5 Tree Diagrams. Each one has a worked solution and a mark scheme showing where the marks go.

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