When θ \theta\,θ is small,
show that cos2θsin2θ\displaystyle \frac{\cos 2\theta}{\sin 2\theta}sin2θcos2θ can be approximated by 2−4θ24θ\displaystyle \frac{2 - 4\theta^2}{4\theta}4θ2−4θ2
278 exam-style questions on Edexcel A Level Maths Radians, covering 5.1 Radian Measure, 5.2 Arc Length, 5.3 Areas of Sectors and Segments, 5.4 Solving Trigonometric Equations, and 5.5 Small Angle Approximations. Each one has a worked solution and a mark scheme showing where the marks go.