Given that θ \theta\,θ is small and is measured in radians, use the small angle approximations to find an approximate value of
5θtan2θcos4θ−1 \frac{5\theta \tan 2\theta}{\cos 4\theta - 1} cos4θ−15θtan2θShow that the expression is approximately −54\displaystyle -\frac{5}{4}−45.
Hence, find an approximate value of
cos4θ−15θtan2θ. \frac{\cos 4\theta - 1}{5\theta \tan 2\theta}. 5θtan2θcos4θ−1.278 exam-style questions on Edexcel A Level Maths Radians, covering 5.1 Radian Measure, 5.2 Arc Length, 5.3 Areas of Sectors and Segments, 5.4 Solving Trigonometric Equations, and 5.5 Small Angle Approximations. Each one has a worked solution and a mark scheme showing where the marks go.