ABC ABC\,ABC is a right angled triangle. Angle BAC=θBAC = \thetaBAC=θ, where θ \theta\,θ is in radians. AB=5AB = 5AB=5 cm.
Given that θ=5−2\theta = \sqrt{5} - 2θ=5−2 is small, find an approximation for the length of ACACAC, giving your answer in exact form.
278 exam-style questions on Edexcel A Level Maths Radians, covering 5.1 Radian Measure, 5.2 Arc Length, 5.3 Areas of Sectors and Segments, 5.4 Solving Trigonometric Equations, and 5.5 Small Angle Approximations. Each one has a worked solution and a mark scheme showing where the marks go.