A particle P P\,P is projected from a point O O\,O with velocity Ums−1U\text{ms}^{-1}Ums−1 at an angle of θ∘ \theta^\circ\,θ∘ to the horizontal. When P P\,P has moved a horizontal distance xxx, its height above O O\,O is yyy.
Show that
y=xtanθ−gx22u2cos2θ y = x \tan \theta - \frac{g x^2}{2 u^2 \cos^2 \theta} y=xtanθ−2u2cos2θgx2Given that θ=45∘\theta = 45^\circθ=45∘ and that when x=48x = 48x=48, y=32y = 32y=32, find the speed of P P\,P at the point where x=48x = 48x=48 and y=32y = 32y=32.
230 exam-style questions on Edexcel A Level Maths Projectiles, covering 6.1 Horizontal Projection, 6.2 Horizontal and Vertical Components, 6.3 Projection at Any Angle, and 6.4 Projectile Motion Formulae. Each one has a worked solution and a mark scheme showing where the marks go.