In this question, use g=9.8 m s−2g = 9.8 \text{ m s}^{-2}g=9.8 m s−2.
A pyrotechnic shell is fired from a launch tube at ground level with an initial velocity of 21 m s−121 \text{ m s}^{-1}21 m s−1 at an angle α\alphaα to the horizontal.
The shell reaches a maximum vertical height of HHH metres.
Show that
H=22.5sin2α H = 22.5 \sin^2 \alpha H=22.5sin2αIn a specific display, the launch angle is constrained such that 0∘≤α≤60∘0^\circ \le \alpha \le 60^\circ0∘≤α≤60∘. Determine the maximum possible height HHH the shell can reach under these conditions.
A technician suggests that using a more massive shell would result in a lower maximum vertical height when launched with the same velocity and angle. Explain whether the technician is correct according to the standard projectile model.
230 exam-style questions on Edexcel A Level Maths Projectiles, covering 6.1 Horizontal Projection, 6.2 Horizontal and Vertical Components, 6.3 Projection at Any Angle, and 6.4 Projectile Motion Formulae. Each one has a worked solution and a mark scheme showing where the marks go.