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1.4 Trigonometry

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Question 23
a.

Show that the equation

1+cos⁡x=3tan⁡xsin⁡x 1 + \cos x = 3 \tan x \sin x 1+cosx=3tanxsinx

Can be written in the form

4cos⁡2x+cos⁡x−3=0 4\cos^2 x + \cos x - 3 = 0 4cos2x+cosx−3=0
[4]
b.

Hence solve, for 0≤x<360∘0 \leq x < 360^\circ0≤x<360∘, the equation,

1+cos⁡x=3tan⁡xsin⁡x 1 + \cos x = 3 \tan x \sin x 1+cosx=3tanxsinx

Give your answers to one decimal place where appropriate.

[5]

1.4 Trigonometry Questions

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