Consider 2sin2x=7cosx+52\sin^2x=7\cos x+52sin2x=7cosx+5.
Show that it can be written as 2cos2x+7cosx+3=02\cos^2x+7\cos x+3=02cos2x+7cosx+3=0.
Hence solve it for 0∘≤x<360∘0^\circ\leq x<360^\circ0∘≤x<360∘.
84 exam-style questions on CCEA A Level Maths 1.4 Trigonometry, covering 1.4.1 Trigonometry, 1.4.2 Trigonometry, 1.4.3 Trigonometry, 1.4.4 Trigonometry, 1.4.5 Trigonometry, 1.4.6 Trigonometry, and 1.4 Trigonometry. Each one has a worked solution and a mark scheme showing where the marks go.