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1.4 Trigonometry

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Question 67

Solve the equation

2cos⁡2x=12 2\cos^2 x = \frac{1}{2} 2cos2x=21​

for 0∘≤x≤360∘0^\circ \le x \le 360^\circ0∘≤x≤360∘.

[4]

1.4 Trigonometry Questions

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