In this question use g=9.8g = 9.8g=9.8 m s−2^{-2}−2.
A particle is projected from the origin with velocity (12i+16j)(12\mathbf{i} + 16\mathbf{j})(12i+16j) m s−1^{-1}−1, where i\mathbf{i}i is horizontal and j\mathbf{j}j is vertically upwards.
Find the position vector of the particle at the instant when it is moving at 45° 45°\,45° below the horizontal.
265 exam-style questions on AQA A Level Maths 3.2 Q: Kinematics, covering 3.2.1 Language of kinematics, 3.2.2 Graphs in kinematics, 3.2.3 Constant acceleration formulae, 3.2.4 Calculus in kinematics (A-level only), and 3.2.5 Motion under gravity and projectiles (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.