A particle moves in a straight line, starting from rest.
At time t t\,t seconds, t≥0t \geq 0t≥0, the acceleration of the particle is a=(6−2t)a = (6 - 2t)a=(6−2t) m s−2^{-2}−2.
Find an expression for the velocity of the particle at time ttt.
Find the maximum velocity of the particle.
265 exam-style questions on AQA A Level Maths 3.2 Q: Kinematics, covering 3.2.1 Language of kinematics, 3.2.2 Graphs in kinematics, 3.2.3 Constant acceleration formulae, 3.2.4 Calculus in kinematics (A-level only), and 3.2.5 Motion under gravity and projectiles (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.