The mass, M M\,M milligrams, of a substance produced in a chemical reaction is modeled by the equation
M=1200e0.4t5+e0.4tt≥0 M = \frac{1200e^{0.4t}}{5 + e^{0.4t}} \quad t \ge 0 M=5+e0.4t1200e0.4tt≥0where t t\,t is the time in hours after the reaction begins.
Determine the initial mass of the substance produced.
Find the upper limit for the mass of the substance according to this model.
Calculate the time, after the start of the reaction, when the mass reaches 900 mg. Give your answer in hours and minutes to the nearest minute.
Show that
dMdt=Ke0.4t(5+e0.4t)2 \frac{dM}{dt} = \frac{Ke^{0.4t}}{(5 + e^{0.4t})^2} dtdM=(5+e0.4t)2Ke0.4twhere K K\,K is a constant to be determined.
Given that at time t=Tt = Tt=T, the rate of production is dMdt=24\displaystyle \frac{dM}{dt} = 24dtdM=24 mg/h, find the value of T T\,T to one decimal place. (Solutions relying entirely on calculator technology are not acceptable.)
Practise AQA A Level Maths 1.10 G: Differentiation with exam-style questions for A Level Maths. 321 questions covering 1.10.1 The derivative and second derivative, 1.10.2 Differentiating standard functions, 1.10.3 Applications of differentiation, 1.10.4 Product, quotient and chain rules (A-level only), 1.10.5 Implicit and parametric differentiation (A-level only), and 1.10.6 Constructing differential equations (A-level only), matched to the AQA A Level Maths (7357) specification and written in Paper 1, Paper 2 and Paper 3 style. Every question includes a full worked solution and mark scheme, so you can see where marks are awarded rather than just whether you got the answer right.
