What is the number of hydrogen atoms in 0.0750 mol of hydrated barium hydroxide, Ba(OH)2⋅8H2O\text{Ba(OH)}_2 \cdot 8\text{H}_2\text{O}Ba(OH)2⋅8H2O?
(Avogadro's constant, NA=6.02×1023 mol−1N_{\text{A}} = 6.02 \times 10^{23}\text{ mol}^{-1}NA=6.02×1023 mol−1)
9.030×10229.030 \times 10^{22}9.030×1022
7.224×10237.224 \times 10^{23}7.224×1023
8.127×10238.127 \times 10^{23}8.127×1023
1.309×10241.309 \times 10^{24}1.309×1024
