Sodium iodate(V) tablets, NaIO3\text{NaIO}_3NaIO3, are sometimes used as a source of iodine in livestock feed. The mass of sodium iodate(V) in a tablet can be determined by reacting it with an aqueous solution of potassium iodide, KI\text{KI}KI, in acidic conditions.
IO3−(aq)+5I−(aq)+6H+(aq)→3I2(aq)+3H2O(l) \text{IO}_3^-(\text{aq}) + 5\text{I}^-(\text{aq}) + 6\text{H}^+(\text{aq}) \rightarrow 3\text{I}_2(\text{aq}) + 3\text{H}_2\text{O}(\text{l}) IO3−(aq)+5I−(aq)+6H+(aq)→3I2(aq)+3H2O(l)An analyst finds that four NaIO3\text{NaIO}_3NaIO3 tablets react with exactly 45.0 cm345.0\text{ cm}^345.0 cm3 of 0.160 mol dm−30.160\text{ mol dm}^{-3}0.160 mol dm−3 KI\text{KI}KI solution.
Calculate the mass, in mg, of NaIO3\text{NaIO}_3NaIO3 in one tablet. Use the following relative atomic masses: Na=23.0\text{Na} = 23.0Na=23.0, I=126.9\text{I} = 126.9I=126.9, O=16.0\text{O} = 16.0O=16.0.
Give your answer to the nearest whole number.
199 exam-style questions on OCR A A Level Chemistry Atoms and reactions, covering Atomic structure and isotopes, Compounds, formulae and equations, Amount of substance, Acids, and Redox. Each one has a worked solution and a mark scheme showing where the marks go.