A solution containing 0.040 mol of phosphoric acid (H3PO4\text{H}_3\text{PO}_4H3PO4) is reacted with 0.150 mol of potassium hydroxide (KOH\text{KOH}KOH) in aqueous solution.
How many molecules of water are formed during this reaction? (Use Avogadro's constant, L=6.02×1023 mol−1L = 6.02 \times 10^{23}\text{ mol}^{-1}L=6.02×1023 mol−1)
2.41×10222.41 \times 10^{22}2.41×1022
3.01×10223.01 \times 10^{22}3.01×1022
7.22×10227.22 \times 10^{22}7.22×1022
9.03×10229.03 \times 10^{22}9.03×1022
