Kinetics

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Question 15
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For a chemical reaction, the relationship between the rate constant, kkk, and the temperature, TTT, is shown by the Arrhenius equation: k=Ae−EaRTk = A e^{-\frac{E_a}{RT}}k=Ae−RTEa​​

For the thermal isomerisation of gaseous cyclopropane:

  • the activation energy, Ea=272 kJ mol−1E_a = 272 \text{ kJ mol}^{-1}Ea​=272 kJ mol−1
  • the Arrhenius constant, A=5.90×1015 s−1A = 5.90 \times 10^{15} \text{ s}^{-1}A=5.90×1015 s−1

At temperature T1T_1T1​, the rate constant is k=6.55×10−4 s−1k = 6.55 \times 10^{-4} \text{ s}^{-1}k=6.55×10−4 s−1.

The Maxwell–Boltzmann distribution curves for the reactant molecules at temperatures T1T_1T1​ and T2T_2T2​ (where T2>T1T_2 > T_1T2​>T1​) are shown below:

Maxwell–Boltzmann Distribution

a.

Calculate the temperature T1T_1T1​ in Kelvin. The gas constant, R=8.31 J K−1 mol−1R = 8.31 \text{ J K}^{-1} \text{ mol}^{-1}R=8.31 J K−1 mol−1

[4]
b.

Explain why the rate of reaction is faster at the higher temperature T2T_2T2​ than at T1T_1T1​, with reference to the Maxwell–Boltzmann distribution shown.

[3]

Kinetics Questions

  1. A Level
  2. /Chemistry
  3. /Kinetics