The thermal decomposition of 1-phenylbut-3-en-1-ol is investigated at different temperatures, TTT:
CH2=CHCH2CH(OH)C6H5→CH2=CHCH3+C6H5CHO\text{CH}_2=\text{CHCH}_2\text{CH(OH)C}_6\text{H}_5 \rightarrow \text{CH}_2=\text{CHCH}_3 + \text{C}_6\text{H}_5\text{CHO}CH2=CHCH2CH(OH)C6H5→CH2=CHCH3+C6H5CHO
The rate constant, kkk, is calculated at each temperature. Some of the results are shown in the table below:
T / K1/T / K−1k / s−1lnk6301.59×10−32.62×10−5−10.556401.56×10−34.60×10−5−9.99650(i)7.97×10−5(ii)6601.52×10−31.36×10−4−8.906701.49×10−32.29×10−4−8.38\begin{aligned} &T \text{ / K} && 1/T \text{ / K}^{-1} && k \text{ / s}^{-1} && \ln k \\ &630 && 1.59 \times 10^{-3} && 2.62 \times 10^{-5} && -10.55 \\ &640 && 1.56 \times 10^{-3} && 4.60 \times 10^{-5} && -9.99 \\ &650 && \mathbf{(i)} && 7.97 \times 10^{-5} && \mathbf{(ii)} \\ &660 && 1.52 \times 10^{-3} && 1.36 \times 10^{-4} && -8.90 \\ &670 && 1.49 \times 10^{-3} && 2.29 \times 10^{-4} && -8.38 \end{aligned}T / K6306406506606701/T / K−11.59×10−31.56×10−3(i)1.52×10−31.49×10−3k / s−12.62×10−54.60×10−57.97×10−51.36×10−42.29×10−4lnk−10.55−9.99(ii)−8.90−8.38
Complete the table with the missing values (i) (to 3 significant figures) and (ii) (to 2 decimal places).
Identify the piece of information in the table column headings that allows the overall order of the reaction to be deduced, and state this overall order.
A graph of lnk\ln klnk against 1T\frac{1}{T}T1 is plotted. The line of best fit has a gradient of −22900 K-22900\text{ K}−22900 K. Calculate the activation energy, EaE_{\text{a}}Ea, in kJ mol−1\text{kJ mol}^{-1}kJ mol−1. (Gas constant R=8.31 J K−1mol−1R = 8.31 \text{ J K}^{-1}\text{mol}^{-1}R=8.31 J K−1mol−1)
1,1-Diphenylbut-3-en-1-ol decomposes in a similar way to 1-phenylbut-3-en-1-ol to produce an alkene and a carbonyl compound. Deduce the structures of the alkene and the carbonyl compound.