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Question 7

Some students design an experiment to investigate the effect of hydrochloric acid (HClHClHCl) concentration on the rate of reaction with calcium carbonate. The apparatus collected carbon dioxide gas in a gas syringe.

Method:

  1. Use a stock solution of 2.5 mol dm−32.5\text{ mol dm}^{-3}2.5 mol dm−3 hydrochloric acid to make a dilution series, including 1.5 mol dm−31.5\text{ mol dm}^{-3}1.5 mol dm−3 and 0.5 mol dm−30.5\text{ mol dm}^{-3}0.5 mol dm−3 acid.
  2. Set up a conical flask containing a fixed mass of calcium carbonate (in excess) and add 25 cm325\text{ cm}^325 cm3 of the acid solution.
  3. Record the volume of carbon dioxide gas collected in the syringe every 15 s15\text{ s}15 s for 1 min1\text{ min}1 min.
  4. Repeat the experiment three times for each concentration.

Some of the results are shown in the tables below:

Table 1: Results for 0.5 mol dm−30.5\text{ mol dm}^{-3}0.5 mol dm−3 HCl

Time (s)Trial 1 (cm3\text{cm}^3cm3)Trial 2 (cm3\text{cm}^3cm3)Trial 3 (cm3\text{cm}^3cm3)Mean (cm3\text{cm}^3cm3)Standard deviation
158988.30.6
3015171616.01.0
4522242323.01.0
6029313030.01.0

Table 2: Results for 2.5 mol dm−32.5\text{ mol dm}^{-3}2.5 mol dm−3 HCl

Time (s)Trial 1 (cm3\text{cm}^3cm3)Trial 2 (cm3\text{cm}^3cm3)Trial 3 (cm3\text{cm}^3cm3)Mean (cm3\text{cm}^3cm3)Standard deviation
1525222524.01.7
3045414644.0[ To be calculated ]
4558545656.02.0
6067616464.03.0
a.

(i) State the independent variable in this investigation.

[1]
b.

(ii) Describe how a student could produce a 1.5 mol dm−31.5\text{ mol dm}^{-3}1.5 mol dm−3 dilute hydrochloric acid solution from the 2.5 mol dm−32.5\text{ mol dm}^{-3}2.5 mol dm−3 stock solution.

[2]
c.

(i) Calculate the standard deviation for the 30 s30\text{ s}30 s result at 2.5 mol dm−32.5\text{ mol dm}^{-3}2.5 mol dm−3 HCl. Use the formula:

s=∑(x−xˉ)2n−1 s = \sqrt{\frac{\sum(x - \bar{x})^2}{n - 1}} s=n−1∑(x−xˉ)2​​

Give your answer to 1 decimal place.

[2]
d.

(ii) Calculate the initial rate of reaction over the first 15 s15\text{ s}15 s for the result at 0.5 mol dm−30.5\text{ mol dm}^{-3}0.5 mol dm−3 HCl. Include the appropriate unit.

[2]

Planning Questions

  1. A Level
  2. /Biology
  3. /Planning