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Radioactivity

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Question 38

This question is about the use of radioactivity to treat tumours in animals.

A dog has a tumour on its leg, which is about 6 millimetres deep. A vet treats the tumour using radiotherapy by injecting a radioactive isotope called phosphorus-32 into the tumour. Phosphorus-32 emits beta particles.

a.

Phosphorus-32 is written using this symbol:

1532P ^{32}_{15}\text{P} 1532​P

How many protons does a nucleus of phosphorus-32 contain?

[1]
b.

How many neutrons does a nucleus of phosphorus-32 contain?

[1]
c.

Phosphorus-31 is a different stable isotope of phosphorus. What are isotopes?

[2]
d.

When phosphorus-32 decays, a beta particle is emitted and it changes into sulfur (S\text{S}S). Complete the nuclear equation by finding the missing mass number A A\,A and atomic number Z Z\,Z for the sulfur nucleus:

1532P→ ZAS+−10β− ^{32}_{15}\text{P} \rightarrow \ ^{A}_{Z}\text{S} + ^{0}_{-1}\beta^{-} 1532​P→ ZA​S+−10​β−
[2]
e.

The tumour is about 6 millimetres deep. Explain why beta radiation is more suitable than alpha or gamma radiations for this treatment.

[3]
f.

The energy from the beta radiation is expected to destroy the cells in the tumour over a treatment period of several weeks.

The most suitable half-life for the radioactive source would be:

  • A 14 minutes
  • B 14 hours
  • C 14 days
  • D 14 years
[1]
g.

Explain your choice.

[2]

Radioactivity Questions

  1. IGCSE
  2. /Physics
  3. /Radioactivity