A drone P P\,P moves in a horizontal plane. At time t t\,t seconds (t≥0t \ge 0t≥0), the velocity of PPP, v m s−1\mathbf{v}\text{ m s}^{-1}v m s−1, is given by
v=(3t2−6t)i+(4t−3)j \mathbf{v} = (3t^2 - 6t)\mathbf{i} + (4t - 3)\mathbf{j} v=(3t2−6t)i+(4t−3)jAt time t=0t = 0t=0, the position vector of P P\,P relative to a fixed origin O O\,O is (5i−2j) m(5\mathbf{i} - 2\mathbf{j})\text{ m}(5i−2j) m.
Find the position vector of P P\,P at the instant when its acceleration is parallel to the vector 3i+2j3\mathbf{i} + 2\mathbf{j}3i+2j.
i\mathbf{i}i
−4i+2j-4\mathbf{i} + 2\mathbf{j}−4i+2j
5j5\mathbf{j}5j
6i+4j6\mathbf{i} + 4\mathbf{j}6i+4j