A student determines the internal diameter ddd of a cylindrical glass container. They add measured volumes of water VVV and record the corresponding depth hhh of the water in the cylinder. The results are shown in the table below:
h / cmV / cm33.0165.5278.03810.54913.060\begin{array}{|c|c|} \hline h \text{ / cm} & V \text{ / cm}^3 \\ \hline 3.0 & 16 \\ \hline 5.5 & 27 \\ \hline 8.0 & 38 \\ \hline 10.5 & 49 \\ \hline 13.0 & 60 \\ \hline \end{array}h / cm3.05.58.010.513.0V / cm31627384960The student plots a graph of VVV (on the yyy-axis) against hhh (on the xxx-axis). Determine the gradient GGG of the best-fit straight line for these data. Show your working.
The internal diameter ddd of the cylindrical glass container is given by the formula:
d=4Gπd = \sqrt{\frac{4G}{\pi}}d=π4GCalculate ddd using your value of GGG. Give your answer to 2 significant figures.
Suggest one practical reason why the measured diameter at the very bottom of the cylinder might deviate from this calculated value.
164 exam-style questions on CIE IGCSE Physics Physical quantities and measurement techniques, covering Physical quantities and measurement techniques. Each one has a worked solution and a mark scheme showing where the marks go.