A small toy drone is flying vertically downwards towards a flat, horizontal mirror on the floor. At a particular instant, the drone is at a height of 2.5 m above the mirror and is descending at a speed of 3.0 m/s.
What is the distance between the drone and its virtual image, and what is the speed of the image relative to the mirror?
Distance =2.5 m= 2.5\text{ m}=2.5 m; Speed =3.0 m/s= 3.0\text{ m/s}=3.0 m/s
Distance =2.5 m= 2.5\text{ m}=2.5 m; Speed =6.0 m/s= 6.0\text{ m/s}=6.0 m/s
Distance =5.0 m= 5.0\text{ m}=5.0 m; Speed =3.0 m/s= 3.0\text{ m/s}=3.0 m/s
Distance =5.0 m= 5.0\text{ m}=5.0 m; Speed =6.0 m/s= 6.0\text{ m/s}=6.0 m/s
216 exam-style questions on CIE IGCSE Physics 3.2 Light, covering 3.2.1a Reflection of light, 3.2.1b Images in a plane mirror, 3.2.2 Refraction of light, 3.2.2a Refraction of light, 3.2.2b Total internal reflection, 3.2.2c Refractive index and critical angle, 3.2.2d Optical fibres, 3.2.3a Converging and diverging lenses, 3.2.3b Ray diagrams and the nature of images, 3.2.3c Virtual images and the magnifying glass, 3.2.3d Correcting long-sightedness and short-sightedness, and 3.2.4 Dispersion of light. Each one has a worked solution and a mark scheme showing where the marks go.