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5.1 Wave behaviour

5.1.1 Describing wave motion

What a wave is

Definition

Wave

A travelling disturbance that transfers energy from one place to another without transferring matter.

Definition

Oscillation

A repeated movement back and forth about a fixed central position.

Definition

Rest position

The undisturbed position that a point in a medium occupies when no wave is passing through it.

  1. A wave is a disturbance that moves through a material or through space, carrying energy from one place to another.
  2. As a wave passes, each point it reaches makes an oscillation, moving back and forth about its rest position.
  3. The points themselves stay in about the same place, so the wave transfers energy without carrying the material along with it.
  4. Flicking one end of a long rope tied to a post sends a hump along the rope, yet each piece of rope only moves up and down as the hump goes by.
  5. A wave that repeats regularly can be described fully using four quantities: amplitude, wavelength, frequency and period.
  6. Amplitude and wavelength are distances, while frequency and period describe the timing of the oscillations.

Amplitude

Definition

Displacement

The distance of a point on a wave from its rest position in a stated direction.

Definition

Amplitude

The maximum displacement of a point on a wave from its rest position.

Definition

Crest

The highest point of a transverse wave, where the displacement above the rest position is greatest.

Definition

Trough

The lowest point of a transverse wave, where the displacement below the rest position is greatest.

  1. As a wave passes, the displacement of each point keeps changing, from zero at the rest position to a maximum on one side and then a maximum on the other side.
  2. On a drawing of a transverse wave, the peaks are called crests and the dips are called troughs.
  3. The amplitude is the height of a crest above the rest position, which is the same as the depth of a trough below it.
  4. Amplitude is always measured from the centre line, which marks the rest position, to the top of a crest or the bottom of a trough.
  5. The vertical distance from the top of a crest to the bottom of a trough is twice the amplitude.
  6. Amplitude is a distance, so it is measured in metres, m\text{m}m, or in centimetres, cm\text{cm}cm, for small waves.
  7. A wave with a larger amplitude carries more energy, so a sound wave with a larger amplitude is louder and a water wave with a larger amplitude rocks a boat harder.
  8. Changing the amplitude does not change how far apart the waves are or how often they arrive, so amplitude is independent of wavelength and frequency.

Wavelength

Definition

Wavelength

The distance from one point on a wave to the equivalent point on the next wave.

  1. The wavelength is the length of one complete wave, measured along the direction in which the wave travels.
  2. Wavelength has the symbol λ\lambdaλ, the Greek letter lambda, and is measured in metres, m\text{m}m.
  3. On a transverse wave, you can measure the wavelength from one crest to the next crest, or from one trough to the next trough.
  4. Any pair of matching points works, as long as both points are at the same stage of the cycle, for example both on the centre line and both about to move upwards.
  5. The distance from a crest to the next trough is only half a wavelength, because a crest and a trough are at opposite stages of the cycle.
  6. Wavelengths vary enormously, from a few centimetres for ripples in a puddle to more than 100 m100\ \text{m}100 m for the long swells that roll onto the beaches of Cornwall.

Frequency and period

Definition

Frequency

The number of complete waves passing a point each second.

Definition

Hertz

The unit of frequency, where one hertz is one complete wave per second.

Definition

Period

The time taken for one complete wave to pass a point.

  1. The frequency of a wave is how many complete waves pass a fixed point every second.
  2. Frequency has the symbol fff and is measured in hertz, Hz\text{Hz}Hz.
  3. A frequency of 50 Hz50\ \text{Hz}50 Hz means that 50 complete waves pass the point each second.
  4. The frequency is set by the source of the wave, so a hand shaking a rope three times every second makes waves with a frequency of 3 Hz3\ \text{Hz}3 Hz.
  5. The period is the time taken for one complete wave to pass a point, which is also the time for one complete oscillation.
  6. Period has the symbol TTT and is measured in seconds, s\text{s}s.
  7. Frequency and period describe the same repeating motion in two ways, so a high frequency always goes with a short period.
  8. The two are linked by T=1fT = \dfrac{1}{f}T=f1​, which can also be written as f=1Tf = \dfrac{1}{T}f=T1​.
  9. A wave with a frequency of 4 Hz4\ \text{Hz}4 Hz has a period of 14=0.25 s\dfrac{1}{4} = 0.25\ \text{s}41​=0.25 s, because four waves share each second equally.
  10. The UK mains supply oscillates at 50 Hz50\ \text{Hz}50 Hz, so each cycle of the mains lasts 150=0.02 s\dfrac{1}{50} = 0.02\ \text{s}501​=0.02 s.

Reading wave graphs

  1. Waves are usually drawn on one of two kinds of graph, so the first thing to check is the label on the horizontal axis.
  2. A displacement-distance graph is like a photograph of the whole wave at one instant, with distance along the wave on the horizontal axis.
  3. On a displacement-distance graph, the horizontal gap between neighbouring crests is the wavelength.
  4. A displacement-time graph follows one single point as time passes, with time on the horizontal axis.
  5. On a displacement-time graph, the horizontal gap between neighbouring crests is the period, which you can turn into a frequency using f=1Tf = \dfrac{1}{T}f=T1​.
  6. On both kinds of graph, the amplitude is read from the vertical axis as the height of a crest above the zero line.
  7. A wavelength can never be read from a displacement-time graph, and a period can never be read from a displacement-distance graph.
Example

Describing a wave on a rope

  • A displacement-distance graph of a wave on a rope shows crests reaching +3.0 cm+3.0\ \text{cm}+3.0 cm and troughs reaching −3.0 cm-3.0\ \text{cm}−3.0 cm.
  • The amplitude is the height of a crest above the zero line, so the amplitude is 3.0 cm3.0\ \text{cm}3.0 cm.
  • The same graph shows four complete waves fitting along 2.0 m2.0\ \text{m}2.0 m of the rope.
λ=2.0 m4=0.50 m \lambda = \frac{2.0\ \text{m}}{4} = 0.50\ \text{m} λ=42.0 m​=0.50 m
  • A displacement-time graph for one point on the rope shows that one complete oscillation takes 0.25 s0.25\ \text{s}0.25 s, so the period is 0.25 s0.25\ \text{s}0.25 s.
f=1T=10.25 s=4.0 Hz f = \frac{1}{T} = \frac{1}{0.25\ \text{s}} = 4.0\ \text{Hz} f=T1​=0.25 s1​=4.0 Hz
  • The wave has an amplitude of 3.0 cm3.0\ \text{cm}3.0 cm, a wavelength of 0.50 m0.50\ \text{m}0.50 m, a period of 0.25 s0.25\ \text{s}0.25 s and a frequency of 4.0 Hz4.0\ \text{Hz}4.0 Hz.
Common Mistake
  • Do not measure amplitude from a crest to a trough, because that distance is twice the amplitude.
  • Do not measure wavelength from a crest to the next trough, because that is only half a wavelength.
  • Do not read a wavelength off a graph with time on the horizontal axis, because the gap between crests on that graph is the period.
Exam technique

Labelling a wave diagram

  • Draw the amplitude arrow vertically from the centre line to the top of a crest.
  • Draw the wavelength arrow horizontally between two matching points, such as crest to crest, so that it covers exactly one full cycle.
  • When you describe frequency, say "complete waves" and "per second", because "how many waves" on its own does not earn the mark.
  • Check the axis label and its unit before you read any value, because a scale in centimetres or milliseconds changes the answer.
Self review
  • What is meant by the amplitude of a wave?
  • Why is the distance from a crest to a trough not equal to the amplitude?
  • What is the difference between the frequency and the period of a wave?
  • What is the period of a wave with a frequency of 10 Hz10\ \text{Hz}10 Hz?
  • Which quantity can you read from a displacement-distance graph but not from a displacement-time graph?

5.1.2 Wavelength and frequency

Defining wavelength

Definition

Wavelength

The distance from one point on a wave to the equivalent point on the next wave.

  1. Wavelength is the distance from one point on a wave to the equivalent point on the next wave.
  2. Two points are equivalent when they are at exactly the same stage of their oscillation, with the same displacement and moving in the same direction.
  3. Crest to crest and trough to trough are the easiest equivalent pairs to spot, but any matching pair gives the same distance.
  4. The symbol for wavelength is λ\lambdaλ and its SI unit is the metre, m\text{m}m.
  5. Short wavelengths are often given in centimetres, where 1 cm=0.01 m1\ \text{cm} = 0.01\ \text{m}1 cm=0.01 m, or in millimetres, where 1 mm=0.001 m1\ \text{mm} = 0.001\ \text{m}1 mm=0.001 m.
  6. Wavelength is a property of the wave in space, so it describes how stretched out the wave pattern is.

Measuring wavelength

  1. Measuring a single wavelength with a ruler gives a large percentage uncertainty, because one wavelength is short compared with the smallest division on the ruler.
  2. A more accurate method is to measure the distance across several complete waves and divide by the number of waves.
  3. Count the gaps between crests rather than the crests themselves, because five crests in a row mark out only four wavelengths.
  4. For example, if six crests span 30 cm30\ \text{cm}30 cm, they mark out five wavelengths, so each wavelength is 30÷5=6.0 cm30 \div 5 = 6.0\ \text{cm}30÷5=6.0 cm.
  5. The distance must be measured along the direction in which the wave is travelling, not across it.

Defining frequency

Definition

Frequency

The number of complete waves passing a point each second.

Definition

Hertz

The unit of frequency, where one hertz is one complete wave per second.

  1. Frequency is the number of complete waves passing a point each second.
  2. This is the same as the number of complete oscillations each point makes per second, because every wave that passes makes the point go through one oscillation.
  3. The symbol for frequency is fff and its unit is the hertz, Hz\text{Hz}Hz, where 1 Hz1\ \text{Hz}1 Hz means one complete wave per second.
  4. Large frequencies are written with prefixes: 1 kHz=1000 Hz1\ \text{kHz} = 1000\ \text{Hz}1 kHz=1000 Hz, 1 MHz=1 000 000 Hz1\ \text{MHz} = 1\,000\,000\ \text{Hz}1 MHz=1000000 Hz and 1 GHz=1 000 000 000 Hz1\ \text{GHz} = 1\,000\,000\,000\ \text{Hz}1 GHz=1000000000 Hz.
  5. Middle C on a piano has a frequency of about 262 Hz262\ \text{Hz}262 Hz, so the piano string vibrates 262 times every second.
  6. The frequency of a wave is fixed by the source that makes it, so it does not depend on the size of the waves.
  7. Frequency is a property of the wave in time, so it describes how often the pattern repeats rather than how stretched out it is.
  8. A louder sound from the same source has a larger amplitude but the same frequency, because the source is still vibrating at the same rate.

Measuring frequency

  1. To find a frequency, pick a fixed point, such as a mark on the side of a ripple tank, and count the complete waves that pass it in a measured time.
  2. Divide the number of complete waves by the time in seconds, so 24 waves in 8.0 s8.0\ \text{s}8.0 s gives a frequency of 3.0 Hz3.0\ \text{Hz}3.0 Hz.
  3. Counting over a longer time, such as 10 s10\ \text{s}10 s rather than 1 s1\ \text{s}1 s, reduces the effect of your reaction time when starting and stopping the stopwatch.
  4. If the period TTT is known instead, the frequency is found from f=1Tf = \dfrac{1}{T}f=T1​.
  5. Sound waves have frequencies far too high to count by eye, so they are measured electronically, for example with a microphone connected to a data logger.
Example

Wavelength and frequency from measurements

  • A photograph of ripples on a pond shows eight crests spread over 1.4 m1.4\ \text{m}1.4 m in the direction the ripples travel.
  • Eight crests mark out seven gaps, so seven wavelengths cover the distance.
λ=1.4 m7=0.20 m \lambda = \frac{1.4\ \text{m}}{7} = 0.20\ \text{m} λ=71.4 m​=0.20 m
  • Standing on the bank, you count 36 complete ripples passing a reed in 12 s12\ \text{s}12 s.
f=3612 s=3.0 Hz f = \frac{36}{12\ \text{s}} = 3.0\ \text{Hz} f=12 s36​=3.0 Hz
  • The ripples have a wavelength of 0.20 m0.20\ \text{m}0.20 m and a frequency of 3.0 Hz3.0\ \text{Hz}3.0 Hz.
Common Mistake
  • Do not define wavelength as the distance from a crest to a trough, because a crest and a trough are not equivalent points.
  • Do not leave out "each second" when you define frequency, because a number of waves on its own is not a frequency.
  • Do not confuse frequency with speed, because frequency counts waves per second while speed measures distance per second.
Exam technique

Writing definitions that score

  • A one-mark definition is marked against key words, so learn each definition word for word.
  • For wavelength, include the words "distance", "same point" or "equivalent point", and "next wave".
  • For frequency, include "number of complete waves", "passing a point" and "per second".
  • If you are asked for the unit of frequency, write "hertz" or Hz\text{Hz}Hz, and never "hertz per second".
Self review
  • What is the definition of wavelength?
  • What does it mean for two points on a wave to be equivalent?
  • How many wavelengths lie between the first crest and the ninth crest of a wave?
  • What is the definition of frequency, and what is its unit?
  • How many hertz are there in 3.5 kHz3.5\ \text{kHz}3.5 kHz?

5.1.3 Wave speed, frequency and wavelength

Wave speed

Definition

Wave speed

The distance travelled by a wave each second.

  1. The wave speed is how fast the wave pattern, and the energy it carries, moves through the medium.
  2. Wave speed has the symbol vvv and is measured in metres per second, m/s\text{m/s}m/s.
  3. Exam questions often call this quantity the wave velocity, and for GCSE calculations the two terms give the same number.
  4. The speed of a wave is set by the medium it travels through, so waves of any frequency travel at the same speed in the same medium.
  5. Ripples in a shallow tray of water travel at only a few tens of centimetres per second, while sound in air travels at about 340 m/s340\ \text{m/s}340 m/s.

The wave equation

  1. Wave speed, frequency and wavelength are linked by the wave equation, v=fλv = f\lambdav=fλ.
  2. In words, wave speed=frequency×wavelength\text{wave speed} = \text{frequency} \times \text{wavelength}wave speed=frequency×wavelength, with speed in m/s\text{m/s}m/s, frequency in Hz\text{Hz}Hz and wavelength in m\text{m}m.
  3. You must learn this equation by heart, because you are expected to recall it rather than look it up.
  4. The equation works because each complete wave that leaves the source is exactly one wavelength long.
  5. If the source makes fff waves every second, then fff wavelengths of new wave are added to the wave train every second.
  6. The front of the wave therefore moves forward a distance of f×λf \times \lambdaf×λ each second, which is its speed.
  7. For example, a source making 5 waves per second, each 2 m2\ \text{m}2 m long, sends the front of the wave forward 10 m10\ \text{m}10 m every second.

How the quantities affect each other

  1. The frequency is fixed by the source and the speed is fixed by the medium, so the wavelength is the quantity that adjusts to fit the equation.
  2. In one medium, where the speed stays constant, frequency and wavelength are inversely proportional.
  3. Doubling the frequency of the source halves the wavelength, because twice as many waves must fit into the same distance each second.
  4. Lowering the frequency spreads the waves out, so the wavelength increases.
  5. If the frequency stays the same but the wave moves into a medium where it travels faster, the wavelength increases in direct proportion to the speed.
  6. Amplitude does not appear in the wave equation, so making a wave bigger does not change its speed, frequency or wavelength.

Waves in a ripple tank

Definition

Ripple tank

A shallow tank of water with a transparent base in which a vibrating dipper makes ripples that can be observed and measured.

Definition

Wavefront

A line joining points on a wave that are at the same stage of their oscillation, such as a line along one crest.

  1. A ripple tank lets you see water waves clearly enough to measure them.
  2. A motor-driven dipper, or a straight wooden bar, touches the water surface and vibrates at a steady frequency, sending out a regular train of ripples.
  3. A lamp above the tank shines through the water, and each crest acts like a lens, casting a bright line onto a white screen or sheet of paper below.
  4. Each bright line marks a wavefront, so the spacing between neighbouring bright lines is one wavelength.
  5. Straight wavefronts travel across the tank at right angles to a ray, which is an arrow drawn to show the direction the waves move.
  6. The top-down view is what you see on the screen, so you measure the wavelength as the gap between neighbouring bright lines along the direction of the ray.

Ripples in a ripple tank shown three ways: a 3D view of the water surface, a side view with crests and troughs one wavelength apart, and a top-down view of straight wavefronts with a ray at right angles showing the direction the waves travel.

Practical

Measuring waves in a ripple tank

  • Aim: to measure the wavelength, frequency and speed of water waves in a ripple tank, and to observe how straight wavefronts reflect from a barrier.
  • Apparatus: ripple tank on a level bench, water, a straight motor-driven dipper connected to a low-voltage power supply, a lamp above the tank, a large sheet of white paper below it, a metre ruler, a stopwatch, a mobile phone camera, a straight plastic barrier and a spirit level.
  • Method, setting up:
    • Pour water into the tank to a depth of about 5 mm5\ \text{mm}5 mm and use the spirit level to make the tank level, so the depth, and therefore the wave speed, is the same everywhere.
    • Lower the dipper until it just touches the surface, switch on the lamp and dim the room lights so the bright lines on the paper are sharp.
    • Switch on the motor and adjust it until a steady pattern of straight, evenly spaced ripples crosses the tank.
  • Method, wavelength:
    • Lay the metre ruler on the paper at right angles to the bright lines.
    • Photograph the pattern with the ruler in view, so that the moving lines can be measured from a still image rather than by eye.
    • On the photograph, measure the distance from the first bright line to the eleventh, which spans ten wavelengths.
    • Divide this distance by ten to find one wavelength.
  • Method, frequency:
    • Choose a fixed mark on the ruler and start the stopwatch as one bright line passes it.
    • Count the bright lines that pass the mark in 10 s10\ \text{s}10 s, and divide the count by 101010 to get the frequency in hertz.
    • For a more reliable count, film the tank in slow motion and count the waves passing the mark frame by frame.
  • Method, speed:
    • Calculate the wave speed from your results using v=fλv = f\lambdav=fλ.
    • As a check, time a single wavefront as it travels a measured distance across the tank, and divide the distance by the time.
    • Repeat each measurement three times and calculate a mean, leaving out any anomalous result.
  • Method, reflection:
    • Stand the straight barrier in the water at an angle to the oncoming wavefronts.
    • Mark the direction of the incoming and reflected wavefronts on the paper, and compare the angles each set makes with the barrier.
  • Results: the wavelength is usually a few centimetres, the two values of speed agree within the uncertainty of the measurements, and the reflected wavefronts leave the barrier at the same angle as the incoming ones arrive with no change in wavelength.
  • Variables: when you change the frequency of the motor to see how the wavelength changes, the frequency is the independent variable, the wavelength is the dependent variable and the water depth is a control variable.
  • Watch out: the bright lines are too quick to measure by eye, so a photograph or slow-motion video is the single biggest improvement to accuracy.
  • Safety: keep the power supply and lamp away from the water, wipe up spills at once so nobody slips, and use only a low-voltage supply for the motor.
Example

Doubling the frequency of a ripple tank

  • A dipper vibrating at 8.0 Hz8.0\ \text{Hz}8.0 Hz makes ripples with a wavelength of 3.0 cm3.0\ \text{cm}3.0 cm.
  • The wavelength is converted to metres before using the equation, so λ=0.030 m\lambda = 0.030\ \text{m}λ=0.030 m.
v=fλ=8.0 Hz×0.030 m=0.24 m/s v = f\lambda = 8.0\ \text{Hz} \times 0.030\ \text{m} = 0.24\ \text{m/s} v=fλ=8.0 Hz×0.030 m=0.24 m/s
  • The dipper frequency is then doubled to 16 Hz16\ \text{Hz}16 Hz while the water depth stays the same, so the speed stays at 0.24 m/s0.24\ \text{m/s}0.24 m/s.
λ=vf=0.24 m/s16 Hz=0.015 m \lambda = \frac{v}{f} = \frac{0.24\ \text{m/s}}{16\ \text{Hz}} = 0.015\ \text{m} λ=fv​=16 Hz0.24 m/s​=0.015 m
  • Doubling the frequency has halved the wavelength to 1.5 cm1.5\ \text{cm}1.5 cm, exactly as the inverse proportion predicts.
Common Mistake
  • Do not assume that a higher frequency makes a wave travel faster, because in the same medium the speed stays the same and the wavelength gets shorter instead.
  • Do not count the bright lines on the screen as wavelengths, because eleven lines mark out only ten wavelengths.
Exam technique

Describing the ripple tank method

  • Name the measuring instrument for each quantity, such as a metre ruler for the wavelength and a stopwatch for the timing.
  • Say that you measure across several waves and divide, and that you repeat readings and calculate a mean.
  • Explain how you would freeze the moving pattern, for example with a photograph or slow-motion video, because this improvement is often credited.
  • Finish by saying how you calculate the speed, using v=fλv = f\lambdav=fλ.
Self review
  • What is the equation linking wave speed, frequency and wavelength?
  • Why does each second of waves add a distance of fλf\lambdafλ to the wave train?
  • What happens to the wavelength if the frequency of a source is tripled and the speed stays the same?
  • Why is the depth of water in a ripple tank kept the same throughout the experiment?
  • Why is it better to measure across ten wavelengths than across one?

5.1.4 Wave speed problems

Using the wave equation

Definition

Wave speed

The distance travelled by a wave each second.

  1. Every wave speed calculation uses the wave equation, v=fλv = f\lambdav=fλ, which you must be able to recall.
  2. Before you start, pick out the two quantities you have been given and the one you need to find.
  3. To find the speed, multiply the frequency by the wavelength: v=fλv = f\lambdav=fλ.
  4. To find the frequency, divide the speed by the wavelength: f=vλf = \dfrac{v}{\lambda}f=λv​.
  5. To find the wavelength, divide the speed by the frequency: λ=vf\lambda = \dfrac{v}{f}λ=fv​.
  6. You can check a rearrangement with simple numbers, such as v=10v = 10v=10, f=2f = 2f=2 and λ=5\lambda = 5λ=5, which fit all three forms.

Units and prefixes

  1. The equation only gives the right answer when every quantity is in its standard unit: m/s\text{m/s}m/s for speed, Hz\text{Hz}Hz for frequency and m\text{m}m for wavelength.
  2. Convert centimetres to metres by dividing by 100100100, so 45 cm=0.45 m45\ \text{cm} = 0.45\ \text{m}45 cm=0.45 m.
  3. Convert millimetres to metres by dividing by 100010001000, so 8 mm=0.008 m8\ \text{mm} = 0.008\ \text{m}8 mm=0.008 m.
  4. Convert kilohertz to hertz by multiplying by 100010001000, so 2.5 kHz=2500 Hz2.5\ \text{kHz} = 2500\ \text{Hz}2.5 kHz=2500 Hz.
  5. Convert megahertz to hertz by multiplying by 1 000 0001\,000\,0001000000, so 3.0 MHz=3.0×106 Hz3.0\ \text{MHz} = 3.0 \times 10^{6}\ \text{Hz}3.0 MHz=3.0×106 Hz.
  6. Very large or very small answers are clearest in standard form, so 0.0015 m0.0015\ \text{m}0.0015 m is written as 1.5×10−3 m1.5 \times 10^{-3}\ \text{m}1.5×10−3 m.
  7. Give the final answer to a sensible number of significant figures, usually the same as the least precise value in the question.

Multi-step problems

  1. Harder questions do not give you fff and λ\lambdaλ directly, so you must work them out from other information first.
  2. If the period is given, find the frequency first using f=1Tf = \dfrac{1}{T}f=T1​.
  3. If a distance covering several waves is given, divide it by the number of waves to get one wavelength.
  4. If you are asked how long a wave takes to travel a distance, find its speed and then use time=distancespeed\text{time} = \dfrac{\text{distance}}{\text{speed}}time=speeddistance​.
  5. Writing down each intermediate value with its unit stops you losing track, and lets the examiner award marks for each correct step.
Example

Speed of a sound wave

  • A sound wave has a frequency of 2.0 kHz2.0\ \text{kHz}2.0 kHz and a wavelength of 17 cm17\ \text{cm}17 cm.
  • Both values are converted to standard units first, giving f=2000 Hzf = 2000\ \text{Hz}f=2000 Hz and λ=0.17 m\lambda = 0.17\ \text{m}λ=0.17 m.
v=fλ v = f\lambda v=fλ v=2000×0.17 v = 2000 \times 0.17 v=2000×0.17 v=340 m/s v = 340\ \text{m/s} v=340 m/s
Example

Wavelength from a period

  • Waves on a lake have a period of 0.50 s0.50\ \text{s}0.50 s and travel at 1.2 m/s1.2\ \text{m/s}1.2 m/s.
  • The frequency is found from the period first.
f=1T=10.50=2.0 Hz f = \frac{1}{T} = \frac{1}{0.50} = 2.0\ \text{Hz} f=T1​=0.501​=2.0 Hz
  • The wave equation is then rearranged to make wavelength the subject.
λ=vf=1.22.0=0.60 m \lambda = \frac{v}{f} = \frac{1.2}{2.0} = 0.60\ \text{m} λ=fv​=2.01.2​=0.60 m
Example

Frequency and travel time on a spring

  • A wave on a long spring travels at 4.5 m/s4.5\ \text{m/s}4.5 m/s, and six complete waves fit along 3.0 m3.0\ \text{m}3.0 m of the spring.
  • One wavelength is 3.0 m÷6=0.50 m3.0\ \text{m} \div 6 = 0.50\ \text{m}3.0 m÷6=0.50 m.
f=vλ=4.50.50=9.0 Hz f = \frac{v}{\lambda} = \frac{4.5}{0.50} = 9.0\ \text{Hz} f=λv​=0.504.5​=9.0 Hz
  • The time for a wave to travel the full 3.0 m3.0\ \text{m}3.0 m of spring comes from the distance and the speed.
t=dv=3.04.5=0.67 s t = \frac{d}{v} = \frac{3.0}{4.5} = 0.67\ \text{s} t=vd​=4.53.0​=0.67 s
Common Mistake
  • Do not substitute a wavelength in centimetres or a frequency in kilohertz without converting it, because the answer will be wrong by a factor of 100100100 or 100010001000.
  • Do not multiply when you should divide, and check that a higher frequency gives a shorter wavelength in your answer.
  • Do not round intermediate values too early, because rounding errors build up in multi-step questions.
Exam technique

Setting out a calculation

  • Write the equation first, either as v=fλv = f\lambdav=fλ or already rearranged, because this alone often earns a mark.
  • Show the substitution with the numbers in standard units, so that a slip on the calculator still leaves you credit for your method.
  • Write the final answer on the answer line with its unit, such as m/s\text{m/s}m/s, Hz\text{Hz}Hz or m\text{m}m.
  • Higher tier questions expect you to rearrange the equation yourself, so practise all three forms until they are automatic.
Self review
  • What are the three rearranged forms of the wave equation?
  • What is 750 mm750\ \text{mm}750 mm in metres?
  • What is the frequency of a wave with a period of 0.20 s0.20\ \text{s}0.20 s?
  • What is the wavelength of a 500 Hz500\ \text{Hz}500 Hz sound wave travelling at 340 m/s340\ \text{m/s}340 m/s?
  • Why should you write down the equation before substituting any numbers?

5.1.5 Transverse and longitudinal waves

Transverse waves

Definition

Transverse wave

A wave in which the oscillations are perpendicular to the direction in which the wave transfers energy.

Definition

Crest

The highest point of a transverse wave, where the displacement above the rest position is greatest.

Definition

Trough

The lowest point of a transverse wave, where the displacement below the rest position is greatest.

  1. In a transverse wave, the oscillations are at right angles, or perpendicular, to the direction in which the wave travels and transfers energy.
  2. If a transverse wave moves from left to right along a rope, each piece of rope moves up and down.
  3. The points displaced furthest one way form the crests, and the points displaced furthest the other way form the troughs.
  4. A transverse wave is drawn as a smooth up-and-down curve, with the wavelength measured from one crest to the next.
  5. Examples of transverse waves include waves on a stretched string or rope, ripples on the surface of water and electromagnetic waves such as light.
  6. A guitar string shows the idea clearly, because the string vibrates sideways while the wave travels along its length.

Longitudinal waves

Definition

Longitudinal wave

A wave in which the oscillations are parallel to the direction in which the wave transfers energy.

Definition

Compression

A region of a longitudinal wave where the particles are pushed closer together than normal.

Definition

Rarefaction

A region of a longitudinal wave where the particles are spread further apart than normal.

  1. In a longitudinal wave, the oscillations are parallel to the direction in which the wave travels and transfers energy.
  2. The particles move backwards and forwards along the same line that the wave is moving along.
  3. As the particles move, they bunch up in some places and spread out in others, forming a repeating pattern of compressions and rarefactions.
  4. In a compression the particles are close together, so the pressure and density there are higher than normal.
  5. In a rarefaction the particles are further apart, so the pressure and density there are lower than normal.
  6. The compressions and rarefactions travel along, but each particle only moves a short distance back and forth about its rest position.
  7. Sound waves are longitudinal, whether they travel through air, water or a solid.
  8. The wavelength of a longitudinal wave is the distance from the centre of one compression to the centre of the next compression.
  9. The amplitude of a longitudinal wave is the greatest distance a particle moves from its rest position along the direction of travel.
  10. A graph of pressure against distance for a sound wave looks like a transverse wave, with peaks at the compressions, but this is only a way of plotting the data and not a picture of how the particles move.

Comparing the two types

  1. The two types of wave are told apart by comparing the direction of oscillation with the direction of energy transfer.
  2. In a transverse wave these two directions are perpendicular, while in a longitudinal wave they are parallel.
  3. Transverse waves are described using crests and troughs, while longitudinal waves are described using compressions and rarefactions.
  4. Both types transfer energy from place to place without carrying the material of the medium along with them.
  5. Both types are described using the same quantities, amplitude, wavelength, frequency and period, and both obey v=fλv = f\lambdav=fλ.
Practical

Making both waves on a slinky

  • Aim: to produce a transverse wave and a longitudinal wave on the same slinky spring, and compare the direction of the oscillations with the direction the wave travels.
  • Apparatus: a long slinky spring, a smooth floor or long bench, a partner, a small piece of coloured ribbon or tape, a metre ruler and a mobile phone to film the motion.
  • Method, transverse wave:
    • Stretch the slinky to about 3 m3\ \text{m}3 m along the floor, with your partner holding the far end still.
    • Tie the ribbon to one coil near the middle of the spring and place the metre ruler beside it to mark its starting position.
    • Move your end sharply from side to side, at right angles to the length of the spring, and keep repeating the movement at a steady rate.
    • Watch the ribbon and note the direction it moves compared with the direction the wave travels along the spring.
  • Method, longitudinal wave:
    • Keep the slinky stretched along the same line.
    • Push your end forwards and pull it back along the length of the spring, again at a steady rate.
    • Look for regions where the coils bunch together and regions where they spread apart, and watch how the ribbon moves.
    • Film both waves in slow motion so you can compare the ribbon's movement frame by frame.
  • Results: in the transverse wave the ribbon moves from side to side at right angles to the spring, while in the longitudinal wave it moves backwards and forwards along the spring as compressions and rarefactions pass.
  • Conclusion: the direction of the ribbon's oscillation, and not the direction of travel, is what tells the two types of wave apart.
  • Watch out: large, jerky hand movements make the pattern messy, so use small, regular movements at a steady rate.
  • Safety: do not let go of a stretched spring, because it can spring back and hit someone, and keep the floor clear so nobody trips.
Common Mistake
  • Do not describe a transverse wave as a wave that "travels up and down", because the wave travels along while only the particles move up and down.
  • Do not compare the oscillations with a vague "movement of the wave", and always compare them with the direction of energy transfer.
Exam technique

Comparing wave types

  • When asked for a difference, write a matched pair of statements, one about transverse waves and one about longitudinal waves.
  • Use the words "perpendicular" or "at right angles" and "parallel", and link each one to the direction of energy transfer.
  • If you are asked for examples, give light or a wave on a string for transverse, and sound for longitudinal.
  • On a diagram of a longitudinal wave, mark the wavelength from the centre of one compression to the centre of the next.
Self review
  • How do the particles move in a transverse wave compared with the direction of energy transfer?
  • What are compressions and rarefactions?
  • Where would you measure the wavelength on a diagram of a longitudinal wave?
  • What is one example of a transverse wave and one example of a longitudinal wave?
  • How does a ribbon on a slinky spring show the difference between the two types of wave?

5.1.6 Sound waves crossing between media

Sound needs a medium

Definition

Medium

The substance, such as air, water or steel, through which a wave travels.

Definition

Sound wave

A longitudinal wave produced by a vibrating object that travels through a medium as a series of compressions and rarefactions.

  1. A sound wave is a longitudinal wave made when a vibrating object pushes and pulls on the particles around it.
  2. Each particle passes the vibration on to its neighbours, so sound can only travel where there are particles to carry it.
  3. The material a wave travels through is its medium, and sound can travel through solids, liquids and gases.
  4. Sound cannot travel through a vacuum, because there are no particles to pass the vibrations on.
  5. An electric bell ringing inside a sealed glass jar goes quiet as the air is pumped out, even though you can still see the hammer striking the bell.

Speed of sound in different media

  1. The speed of sound depends on the medium, and it is usually fastest in solids, slower in liquids and slowest in gases.
  2. Typical values are about 340 m/s340\ \text{m/s}340 m/s in air, about 1500 m/s1500\ \text{m/s}1500 m/s in water and about 6000 m/s6000\ \text{m/s}6000 m/s in steel.
  3. In a solid, the particles are packed closely together and held by strong forces, so each vibration is passed to the next particle very quickly.
  4. In a gas, the particles are far apart and only pass on a vibration when they collide, so the disturbance travels much more slowly.
  5. The speed of sound in a gas also increases with temperature, because faster-moving particles pass the vibration on sooner.

Crossing a boundary

  1. When sound passes from one medium into another, its speed changes, because the new medium passes vibrations along at a different rate.
  2. The frequency does not change, because the particles at the boundary are forced to vibrate at the same rate as the particles hitting them.
  3. Every vibration that reaches the boundary in one second is passed on in that same second, so the number of waves per second is the same on both sides.
  4. Since v=fλv = f\lambdav=fλ and fff stays fixed, the wavelength must change in the same proportion as the speed.
  5. If the sound speeds up as it enters the new medium, its wavelength increases, so the compressions spread further apart.
  6. If the sound slows down as it enters the new medium, its wavelength decreases, so the compressions crowd closer together.
  7. For the same frequency, λ2λ1=v2v1\dfrac{\lambda_2}{\lambda_1} = \dfrac{v_2}{v_1}λ1​λ2​​=v1​v2​​, so tripling the speed triples the wavelength.
  8. A swimmer under water hears a whistle from the poolside as the same note, because the frequency is unchanged, even though its wavelength in the water is more than four times longer.
Example

Sound passing from air into water

  • A whistle at the side of a swimming pool produces sound with a frequency of 850 Hz850\ \text{Hz}850 Hz.
  • In air the sound travels at 340 m/s340\ \text{m/s}340 m/s.
λair=vf=340850=0.40 m \lambda_{\text{air}} = \frac{v}{f} = \frac{340}{850} = 0.40\ \text{m} λair​=fv​=850340​=0.40 m
  • When the sound enters the water its frequency stays at 850 Hz850\ \text{Hz}850 Hz, but its speed rises to 1500 m/s1500\ \text{m/s}1500 m/s.
λwater=1500850=1.8 m \lambda_{\text{water}} = \frac{1500}{850} = 1.8\ \text{m} λwater​=8501500​=1.8 m
  • The speed has increased, so the wavelength has increased, while the frequency is unchanged.
Example

Sound passing from steel into air

  • A hammer strikes one end of a steel railing, sending sound along it at 6000 m/s6000\ \text{m/s}6000 m/s with a wavelength of 2.4 m2.4\ \text{m}2.4 m.
f=vλ=60002.4=2500 Hz f = \frac{v}{\lambda} = \frac{6000}{2.4} = 2500\ \text{Hz} f=λv​=2.46000​=2500 Hz
  • The sound passes from the railing into the air with the same frequency of 2500 Hz2500\ \text{Hz}2500 Hz.
λair=3402500=0.14 m \lambda_{\text{air}} = \frac{340}{2500} = 0.14\ \text{m} λair​=2500340​=0.14 m
  • The sound slows down by a factor of about 181818 as it enters the air, so its wavelength becomes about 181818 times shorter.
Common Mistake
  • Do not say that the frequency of sound changes when it enters a new medium, because the frequency is fixed by the source.
  • Do not say that sound travels faster in air than in solids, because the closely packed particles of a solid pass vibrations on much faster.
Exam technique

Explaining a change of medium

  • Start by stating what happens to the speed, and give the reason that the new medium passes vibrations on at a different rate.
  • State clearly that the frequency stays the same, and explain why.
  • Link the two with v=fλv = f\lambdav=fλ to conclude what happens to the wavelength, using the word "increases" or "decreases".
  • In a calculation, use the speed for the correct medium and the same frequency on both sides of the boundary.
Self review
  • Why can sound not travel through a vacuum?
  • In which state of matter does sound usually travel fastest, and why?
  • What happens to the frequency of a sound wave as it passes from air into water?
  • What happens to the wavelength of a sound wave when it slows down on entering a new medium?
  • What is the frequency of a sound with a wavelength of 0.50 m0.50\ \text{m}0.50 m travelling through air at 340 m/s340\ \text{m/s}340 m/s?

5.1.7 Reflection, transmission and absorption at interfaces

Waves at an interface

Definition

Interface

The boundary where two different materials meet.

Definition

Reflection

The change in direction of a wave at an interface so that it travels back into the material it came from.

Definition

Transmission

The passing of a wave through an interface so that it carries on travelling into the second material.

Definition

Absorption

The transfer of energy from a wave to the material it is travelling through or striking.

  1. An interface is the boundary between two materials, such as air and glass, water and the seabed, or air and a brick wall.
  2. When a wave reaches an interface, its energy can be reflected, transmitted or absorbed.
  3. In reflection, the wave bounces back into the material it came from.
  4. In transmission, the wave passes through the interface and carries on into the second material.
  5. In absorption, energy from the wave is transferred to the material, usually increasing its thermal energy store so it warms up slightly.
  6. At most interfaces all three happen at once, with the wave's energy shared between them.
  7. A window transmits most of the light that reaches it, reflects a little so you can see a faint reflection, and absorbs a small amount.
  8. How the energy is shared depends on the two materials, on the wavelength of the wave and on the angle at which it arrives.
  9. Energy is always conserved, so the energy reflected, transmitted and absorbed adds up to the energy that arrived.

Reflection and echoes

Definition

Normal

An imaginary line drawn at right angles to a surface at the point where a ray meets it.

Definition

Angle of incidence

The angle between an incoming ray and the normal at the point where the ray meets a surface.

Definition

Angle of reflection

The angle between a reflected ray and the normal at the point where the ray leaves a surface.

Definition

Echo

A reflected sound wave that is detected a short time after the original sound.

  1. Reflection is strongest when a wave meets a surface it cannot easily pass into, such as light hitting a mirror or sound hitting a hard wall.
  2. To describe a reflection, you draw a normal, an imaginary line at right angles to the surface where the wave strikes it.
  3. The angle of incidence is measured between the incoming ray and the normal.
  4. The angle of reflection is measured between the reflected ray and the normal.
  5. For a smooth, flat surface, the law of reflection states that the angle of incidence is equal to the angle of reflection.
  6. A reflected sound wave is called an echo, and you hear it as a separate sound if it returns more than about 0.1 s0.1\ \text{s}0.1 s after the original.
  7. Hard, smooth surfaces such as tiled walls reflect sound well, which is why a school sports hall or a swimming pool sounds so echoey.
  8. Soft, uneven materials such as curtains, carpets and foam panels absorb much more of the sound, so recording studios and cinemas line their walls with them.

Ultrasound and sonar

Definition

Ultrasound

Sound with a frequency above 20 000 Hz, which is too high for humans to hear.

Definition

Sonar

A system that sends pulses of sound or ultrasound through water and times the returning echoes to locate objects or measure depth.

  1. Ultrasound is sound with a frequency above 20 000 Hz20\,000\ \text{Hz}20000 Hz, which is too high for humans to hear.
  2. When ultrasound reaches the boundary between two different materials, part of it is reflected and the rest is transmitted onwards.
  3. Each boundary the ultrasound reaches sends back a weaker echo, so a single pulse produces a series of echoes from boundaries at different depths.
  4. Timing each echo shows how far away each boundary is, which allows structures that cannot be seen directly, such as an unborn baby, to be mapped.
  5. Sonar uses the same idea under water, with a ship sending a pulse of sound or ultrasound down to the seabed and timing how long the echo takes to return.
  6. The pulse travels down to the seabed and back up again, so the depth is half of the total distance the pulse travels.
  7. This gives depth=speed×time2\text{depth} = \dfrac{\text{speed} \times \text{time}}{2}depth=2speed×time​.
  8. Fishing boats use sonar to find shoals of fish, and survey ships use it to map the shape of the seabed and to find shipwrecks.

Refraction at an interface

Definition

Refraction

The change in direction of a wave as it crosses an interface at an angle, caused by a change in its speed.

  1. When a transmitted wave crosses an interface at an angle, it can change direction, and this is called refraction.
  2. Refraction happens because the wave changes speed as it moves into the new material.
  3. Light slows down as it passes from air into glass and bends towards the normal, then speeds up as it leaves and bends away from the normal.
  4. A wave that meets the interface along the normal changes speed but does not change direction.
Practical

Reflection from a plane mirror

  • Aim: to show that the angle of reflection from a plane mirror is equal to the angle of incidence.
  • Apparatus: a ray box with a single narrow slit, a low-voltage power supply, a plane mirror in a holder, a sheet of plain A3 paper, a sharp pencil, a ruler and a protractor.
  • Method:
    • Draw a straight line across the middle of the paper and stand the mirror upright with its reflecting surface exactly on the line.
    • Use the protractor to draw a normal at 90∘90^\circ90∘ to the mirror line, then draw lines from the foot of the normal at 20∘20^\circ20∘, 30∘30^\circ30∘, 40∘40^\circ40∘, 50∘50^\circ50∘, 60∘60^\circ60∘ and 70∘70^\circ70∘ to it.
    • Dim the room and shine a narrow ray from the ray box along the 20∘20^\circ20∘ line, so that it hits the mirror exactly where the normal meets it.
    • Mark the path of the reflected ray with two small crosses placed as far apart as possible.
    • Repeat for each of the other incident lines, labelling each pair of crosses with its angle.
    • Remove the mirror, join each pair of crosses back to the foot of the normal with a ruler, and measure each angle of reflection from the normal.
    • Record the results in a table of angle of incidence against angle of reflection.
  • Results: each angle of reflection matches its angle of incidence to within one or two degrees, which confirms the law of reflection.
  • Variables: the angle of incidence is the independent variable, the angle of reflection is the dependent variable, and the mirror and the width of the ray are kept the same.
  • Watch out: a wide ray makes it hard to judge where the beam is, so use the narrowest slit and always mark the centre of the ray.
  • Safety: the ray box lamp gets hot, so do not touch the casing, and keep the room bright enough to move around safely.
Practical

Refraction through a glass block

  • Aim: to trace the path of a ray of light through a rectangular glass block and observe how it changes direction at each interface.
  • Apparatus: a ray box with a single narrow slit, a low-voltage power supply, a rectangular glass block or a triangular prism, a sheet of plain A3 paper, a sharp pencil, a ruler and a protractor.
  • Method:
    • Place the glass block in the middle of the paper and draw carefully around its outline with a sharp pencil.
    • Shine a narrow ray at one long side of the block at an angle, so that it enters part way along that side.
    • Mark the incoming ray with two crosses and the ray leaving the opposite side with two more crosses.
    • Remove the block, join the crosses, and then join the entry point to the exit point to show the path of the ray inside the glass.
    • Draw a normal at the entry point and at the exit point, and measure the angle between each ray and its normal.
    • Repeat for several different angles of incidence, and once with the ray striking the block along the normal.
  • Results: the ray bends towards the normal as it enters the glass and away from the normal as it leaves, while the ray along the normal passes straight through without bending.
  • Observation: a faint reflected ray can also be seen at each surface, showing that some light is reflected while most is transmitted.
  • Watch out: a blunt pencil gives a thick outline that makes the entry and exit points uncertain, so keep the pencil sharp and do not let the block move.
  • Safety: handle the glass block carefully because chipped edges can cut, and let the ray box cool before packing it away.
Example

Measuring the depth of the sea

  • A ship's sonar sends a pulse of ultrasound straight down and detects the echo 0.40 s0.40\ \text{s}0.40 s later.
  • Sound travels through sea water at 1500 m/s1500\ \text{m/s}1500 m/s.
  • The total distance travelled, down to the seabed and back, is found first.
d=v×t=1500×0.40=600 m d = v \times t = 1500 \times 0.40 = 600\ \text{m} d=v×t=1500×0.40=600 m
  • The pulse has made a round trip, so the depth is half of this distance.
depth=6002=300 m \text{depth} = \frac{600}{2} = 300\ \text{m} depth=2600​=300 m
Common Mistake
  • Do not say that absorbed energy disappears, because it is transferred to the material and usually warms it.
  • Do not forget to halve the distance in an echo calculation, because the sound travels to the surface and back.
  • Do not measure the angles of incidence and reflection from the surface, because both are always measured from the normal.
Exam technique

Describing what happens at an interface

  • Name all three effects, reflection, transmission and absorption, and say what happens to the wave's energy in each.
  • Use a specific example, such as sonar echoes from the seabed or light passing through a window, to show you can apply the idea.
  • In an echo calculation, write down the total distance before halving it, so the method mark is clear.
  • For the mirror or glass block practical, mention drawing the normal, using a narrow ray, marking the ray with crosses and measuring with a protractor.
Self review
  • What are the three things that can happen to a wave at an interface?
  • What does the law of reflection state?
  • Why is the distance in a sonar calculation divided by two?
  • What happens to the energy of a wave that is absorbed?
  • What happens to a ray of light that enters a glass block along the normal?

5.1.8 Sound waves and vibrations in solids

Vibrations and sound

Definition

Vibration

A rapid back-and-forth movement of an object or of particles about a fixed position.

Definition

Sound wave

A longitudinal wave produced by a vibrating object that travels through a medium as a series of compressions and rarefactions.

  1. A sound wave and the vibration of a solid object are two forms of the same disturbance, and each can be turned into the other.
  2. A vibrating surface in contact with air pushes on the air as it moves outwards and pulls back as it moves inwards.
  3. Moving outwards squeezes the nearby air particles together into a compression.
  4. Moving back inwards leaves extra space, so the air particles spread out into a rarefaction.
  5. Each cycle of the surface's vibration produces one compression and one rarefaction, so the sound wave has the same frequency as the vibrating object.
  6. The reverse also happens, because the changing pressure of a sound wave pushes and pulls on any solid surface it reaches and makes that surface vibrate.
  7. In both directions energy is transferred, but no material travels from the source to the receiver.

Solids producing sound

  1. A loudspeaker contains a light paper or plastic cone that an electrical signal forces to vibrate back and forth, sending sound waves into the air.
  2. A plucked guitar string vibrates, but the thin string moves very little air on its own.
  3. The string passes its vibrations through the bridge to the hollow wooden sound box, whose large surface pushes on far more air and makes the sound much louder.
  4. A tuning fork has two metal prongs that vibrate at one fixed frequency when struck, producing a pure note.
  5. Pressing the base of a vibrating tuning fork onto a wooden table makes the note louder, because the large table top is forced to vibrate and pushes on more air.
  6. A drum skin vibrates when it is struck, and its large area creates strong compressions and rarefactions in the air.

Sound making solids vibrate

  1. When sound waves reach a microphone, they make a thin, flexible diaphragm vibrate, and the microphone turns these vibrations into an electrical signal.
  2. A loud bass note from a passing car can make a shop window rattle, because the sound waves force the glass to vibrate.
  3. Music from next door reaches you because the sound waves make the dividing wall vibrate, the vibrations travel through the bricks, and the far side of the wall then produces new sound waves in your room.
  4. Your own ear works in the same way, using a chain of solid parts to turn sound waves into vibrations and then into electrical signals.

Structure of the ear

Definition

Eardrum

A thin, tightly stretched membrane at the inner end of the ear canal that vibrates when sound waves reach it.

Definition

Ossicles

The three tiny linked bones of the middle ear, the hammer, anvil and stirrup, that pass vibrations from the eardrum to the inner ear.

Definition

Cochlea

A coiled, fluid-filled tube in the inner ear whose hair cells turn vibrations into electrical signals.

Definition

Auditory nerve

The nerve that carries electrical signals from the cochlea to the brain.

  1. The outer ear, or pinna, is the visible flap that collects sound waves and funnels them into the ear canal.
  2. Sound waves travel down the air-filled ear canal to the eardrum, a thin membrane stretched across its inner end.
  3. The changing pressure of the sound wave makes the eardrum vibrate at the same frequency as the sound.
  4. In the air-filled middle ear, the eardrum is linked to three tiny bones called the ossicles: the hammer, the anvil and the stirrup.
  5. The ossicles act as levers that pass the vibrations along and amplify them, increasing the force of each vibration.
  6. The stirrup presses against a small membrane called the oval window, which is the entrance to the inner ear.
  7. The vibrating oval window sets up waves in the fluid inside the cochlea, a coiled tube in the inner ear.
  8. Tiny hair cells lining the cochlea are moved by the fluid and produce electrical signals.
  9. The auditory nerve carries these signals to the brain, which interprets them as sound.
  10. Along this route the disturbance changes form several times: a sound wave in air, vibrations of solid parts, waves in the fluid of the cochlea, and finally electrical signals.
Example

Tracing a guitar note to the brain

  • A plucked guitar string vibrates, and its vibrations pass through the bridge into the sound box.
  • The sound box vibrates and produces compressions and rarefactions in the surrounding air.
  • These travel to a listener's ear as a longitudinal sound wave with the same frequency as the string.
  • The sound wave makes the eardrum vibrate, and the ossicles pass the vibrations on and amplify them.
  • The stirrup vibrates the oval window, which sets up waves in the fluid of the cochlea.
  • Hair cells in the cochlea respond to the moving fluid and send electrical signals along the auditory nerve to the brain.
Common Mistake
  • Do not say that air particles travel from the guitar to your ear, because each particle only vibrates about its rest position while the energy is passed along.
  • Do not say that the ossicles turn sound into electrical signals, because that happens in the cochlea.
Exam technique

Describing a conversion

  • Give the steps in order, naming the part that vibrates at each stage.
  • Use the words "compression" and "rarefaction" when you describe how a vibrating solid makes a sound wave.
  • When you describe how sound makes a solid vibrate, say that the changing pressure exerts a changing force on the surface.
  • For the ear, name at least the eardrum, the ossicles, the cochlea and the auditory nerve, in that order.
Self review
  • How does a vibrating loudspeaker cone produce compressions and rarefactions?
  • Why does a guitar need a sound box?
  • What is the job of the ossicles?
  • Where in the ear are vibrations turned into electrical signals?
  • How can music played in one room make the air vibrate in the next room?

5.1.9 Frequency range and human hearing

Why the frequency range is limited

Definition

Natural frequency

The frequency at which an object vibrates when it is disturbed and then left to vibrate on its own.

Definition

Resonance

The large increase in the amplitude of an object's vibration when it is driven at its natural frequency.

  1. Every solid part that converts sound into vibration, such as an eardrum or a microphone diaphragm, has mass and stiffness.
  2. Together, the mass and stiffness give the part a natural frequency at which it vibrates most easily.
  3. When sound drives the part at or near its natural frequency, it vibrates with a large amplitude, an effect called resonance.
  4. The further the frequency of the sound is from the natural frequency, the smaller the amplitude of the vibration becomes.
  5. At very high frequencies, the part's mass gives it too much inertia to reverse direction quickly enough, so it barely moves.
  6. At very low frequencies, the slow pressure changes are too weak compared with the part's stiffness to make it vibrate usefully.
  7. Outside a certain range of frequencies, the vibrations are so small that no useful signal is produced.
  8. This is why every microphone and loudspeaker has a stated frequency range, and why small earphones struggle to reproduce deep bass notes.
  9. The same limit applies in reverse, because a solid can only produce sound waves over the range of frequencies at which it can vibrate.

Graph of the amplitude of a vibrating part against the frequency of the sound driving it, rising to a peak at the natural frequency and falling away at higher and lower frequencies, which is why a part only responds well over a limited range.

The range of human hearing

Definition

Audible range

The range of sound frequencies a person can hear, about 20 Hz to 20 000 Hz for a young person with healthy hearing.

Definition

Infrasound

Sound with a frequency below 20 Hz, which is too low for humans to hear.

Definition

Ultrasound

Sound with a frequency above 20 000 Hz, which is too high for humans to hear.

Definition

Pitch

How high or low a sound seems to a listener, which is set by the frequency of the sound wave.

  1. The human ear can only turn sound into nerve signals over a limited range of frequencies, called the audible range.
  2. For a young person with healthy hearing, this range is about 20 Hz20\ \text{Hz}20 Hz to 20 000 Hz20\,000\ \text{Hz}20000 Hz, or 20 kHz20\ \text{kHz}20 kHz.
  3. Sound below 20 Hz20\ \text{Hz}20 Hz is called infrasound, and sound above 20 000 Hz20\,000\ \text{Hz}20000 Hz is called ultrasound.
  4. Infrasound and ultrasound are still sound waves that carry energy, but the parts of the ear cannot respond to them strongly enough to produce signals.
  5. Within the audible range, the frequency of a sound sets its pitch, so a higher frequency is heard as a higher note.
  6. The ear is most sensitive to frequencies of a few thousand hertz, which helps you pick out the sounds of speech.
  7. Other animals have ears built differently, so dogs can hear up to about 45 000 Hz45\,000\ \text{Hz}45000 Hz, bats hear well above 100 000 Hz100\,000\ \text{Hz}100000 Hz, and elephants communicate using infrasound.

How hearing changes with age

Definition

Hair cells

Sensory cells lining the cochlea that produce electrical signals when the fluid around them vibrates.

  1. Inside the cochlea, rows of hair cells each respond best to a particular frequency.
  2. Hair cells near the entrance of the cochlea respond to high frequencies, while those deep inside the coil respond to low frequencies.
  3. Hair cells are gradually damaged over a lifetime and, unlike many cells in the body, they are not replaced.
  4. The cells that detect high frequencies are usually lost first, so the upper limit of hearing falls as people get older.
  5. By middle age many adults cannot hear sounds above about 15 000 Hz15\,000\ \text{Hz}15000 Hz, and the limit keeps dropping with age.
  6. The eardrum and ossicles can also become stiffer with age, so they pass on vibrations less well.
  7. Repeated exposure to loud sound, such as from concerts, power tools or earphones turned up high, damages hair cells faster and brings hearing loss on earlier.
  8. Some UK shops have used devices that give out a tone of about 17 000 Hz17\,000\ \text{Hz}17000 Hz to stop groups gathering outside, because most teenagers can hear it while most older adults cannot.
Example

Deciding which sounds can be heard

  • A dog whistle produces sound at 25 000 Hz25\,000\ \text{Hz}25000 Hz, which is above the upper limit of 20 000 Hz20\,000\ \text{Hz}20000 Hz, so it is ultrasound and people cannot hear it.
  • A dog can hear the same whistle, because its audible range extends to about 45 000 Hz45\,000\ \text{Hz}45000 Hz.
  • A distant thunderstorm produces some sound at 10 Hz10\ \text{Hz}10 Hz, which is below 20 Hz20\ \text{Hz}20 Hz, so this part of the sound is infrasound and is not heard.
  • A test tone at 17 000 Hz17\,000\ \text{Hz}17000 Hz is heard by a teenager but not by a 60-year-old, because the older person has lost many of the hair cells that detect high frequencies.
Common Mistake
  • Do not say that sounds outside the audible range are not sound waves, because infrasound and ultrasound are sound waves that the ear cannot detect.
  • Do not confuse pitch with loudness, because pitch depends on frequency while loudness depends on amplitude.
Exam technique

Explaining the limited range

  • Link the frequency of the sound to how well a solid part, such as the eardrum, can vibrate at that frequency.
  • Say that each part responds strongly near its natural frequency and only weakly far from it.
  • Quote the range of human hearing with units, as 20 Hz20\ \text{Hz}20 Hz to 20 000 Hz20\,000\ \text{Hz}20000 Hz.
  • For ageing, say that hair cells in the cochlea, especially those for high frequencies, are damaged and not replaced, so the upper limit of hearing falls.
Self review
  • Why can a microphone diaphragm only respond well over a limited range of frequencies?
  • What is resonance?
  • What is the audible range for a young person with healthy hearing?
  • What is the difference between infrasound and ultrasound?
  • Why do older people often fail to hear very high-pitched sounds?

5.1.10 Modelling waves with water ripples and sound

Ripples as a model of transverse waves

Definition

Ripple tank

A shallow tank of water with a transparent base in which a vibrating dipper makes ripples that can be observed and measured.

Definition

Wavefront

A line joining points on a wave that are at the same stage of their oscillation, such as a line along one crest.

Definition

Stroboscope

A lamp that flashes at an adjustable frequency so that a repeating motion, such as a train of ripples, appears to stand still.

  1. Waves on the surface of water are slow and easy to see, so ripples are used as a model of transverse waves in general.
  2. As a ripple passes, each bit of the water surface moves mainly up and down while the ripple itself travels across the surface.
  3. The oscillation of the surface is at right angles to the direction of travel, which is the key feature of a transverse wave.
  4. Real water waves are not perfectly transverse, because the water also moves slightly back and forth, so each bit of the surface traces out a small loop.
  5. A ripple tank makes ripples visible, because a lamp above the tank shines through the water and each crest focuses the light into a bright line on a screen below.
  6. The bright lines are the wavefronts, so the spacing between them shows the wavelength directly.
  7. A stroboscope flashing at the same frequency as the dipper makes the pattern appear to freeze, which makes the wavelength much easier to measure.
  8. Ripples in shallow water travel at only a few tens of centimetres per second, so their speed can be measured with simple equipment.

Sound in air is longitudinal

Definition

Longitudinal wave

A wave in which the oscillations are parallel to the direction in which the wave transfers energy.

Definition

Compression

A region of a longitudinal wave where the particles are pushed closer together than normal.

Definition

Rarefaction

A region of a longitudinal wave where the particles are spread further apart than normal.

  1. Sound cannot be seen, but it travels through air as a longitudinal wave.
  2. A vibrating source pushes and pulls on the air, producing compressions and rarefactions that move away from it.
  3. Each air particle vibrates backwards and forwards parallel to the direction the sound travels.
  4. Sound in air travels at about 340 m/s340\ \text{m/s}340 m/s, roughly a thousand times faster than ripples in a tank, so measuring its speed needs a long distance or very fast electronic timing.
  5. You notice the speed of sound when you see a firework burst before you hear the bang, because light reaches you almost instantly while sound takes about 3 s3\ \text{s}3 s to travel 1 km1\ \text{km}1 km.

Measuring the speed of each wave

  1. Both speeds are found from speed=distancetime\text{speed} = \dfrac{\text{distance}}{\text{time}}speed=timedistance​, or from v=fλv = f\lambdav=fλ when the frequency and wavelength can be measured.
  2. For ripples, the distances and times are short, so filming the tank gives far more reliable timing than a hand-held stopwatch.
  3. For sound, a stopwatch is far too slow over a short distance, so you need either a very long distance or an electronic timer triggered by microphones.
Practical

Speed of water ripples

  • Aim: to measure the speed of water ripples by timing a single wavefront over a measured distance.
  • Apparatus: a ripple tank, water, a straight dipper with a motor and low-voltage supply, a lamp, a white screen or sheet of paper, a metre ruler, and a mobile phone that can record slow-motion video.
  • Method:
    • Fill the tank to a constant depth of about 5 mm5\ \text{mm}5 mm and check with a spirit level that it is level.
    • Lay the metre ruler across the bottom of the tank in the direction the ripples will travel, so that its shadow appears on the screen at the same scale as the ripples.
    • Choose two marks on the ruler's shadow that are 40 cm40\ \text{cm}40 cm apart.
    • Switch on the dipper briefly to send a short train of ripples across the tank.
    • Film the screen in slow motion, then play the video back and find the time for one bright wavefront to travel from the first mark to the second.
    • Calculate the speed using v=dtv = \dfrac{d}{t}v=td​.
    • Repeat at least three times and calculate a mean, leaving out any anomalous result.
  • Second method: freeze the pattern with a stroboscope or a photograph, measure across ten wavelengths, read the frequency from the dipper's signal generator and calculate v=fλv = f\lambdav=fλ.
  • Results: ripples in shallow water typically travel at about 0.2 m/s0.2\ \text{m/s}0.2 m/s to 0.3 m/s0.3\ \text{m/s}0.3 m/s, and the two methods should give similar values.
  • Watch out: the pattern on the screen is magnified by the spreading light, so always measure against the shadow of the ruler rather than a ruler lying on the screen.
  • Safety: keep the electrical equipment away from the water and wipe up any spills straight away.
Practical

Speed of sound in air

  • Aim: to measure the speed of sound in air using two microphones and an electronic timer.
  • Apparatus: two microphones, a fast electronic timer or data logger that reads to at least 0.0001 s0.0001\ \text{s}0.0001 s, a tape measure, and two wooden blocks to make a sharp sound.
  • Method, two microphones:
    • Place the two microphones in a straight line with the sound source, with a measured gap of 1.00 m1.00\ \text{m}1.00 m between them.
    • Connect the first microphone so that it starts the timer and the second so that it stops it.
    • Clap the blocks together sharply just beyond the first microphone, on the same line.
    • Record the time interval, which is the time the sound takes to travel from the first microphone to the second.
    • Repeat several times, calculate a mean time and use v=dtv = \dfrac{d}{t}v=td​ to find the speed.
    • Repeat with larger gaps between the microphones to check that the speed stays the same.
  • Method, echo:
    • Stand at a measured distance, such as 50 m50\ \text{m}50 m, from a large, flat wall in an open space.
    • Clap at a steady rhythm, adjusting it until each clap happens exactly as the echo of the previous clap returns.
    • Have a partner time 20 claps, then divide by 20 to find the time between claps.
    • In that time the sound travels to the wall and back, so the distance is 2×50=100 m2 \times 50 = 100\ \text{m}2×50=100 m.
  • Results: the speed of sound in air is about 340 m/s340\ \text{m/s}340 m/s, so with a 1.00 m1.00\ \text{m}1.00 m gap the timer reads about 0.0029 s0.0029\ \text{s}0.0029 s.
  • Watch out: a soft or drawn-out sound may not trigger the microphones cleanly, so use a single sharp sound and keep the room quiet.
  • Safety: keep the sounds at a sensible volume to protect your hearing, and do the echo method well away from roads.

Refraction in a ripple tank

Definition

Refraction

The change in direction of a wave as it crosses an interface at an angle, caused by a change in its speed.

  1. The speed of ripples depends on the depth of the water, and they travel more slowly in shallower water.
  2. Placing a sheet of clear plastic or glass in part of the tank creates a shallow region with a sharp boundary.
  3. Ripples crossing into the shallow region slow down, and because their frequency is fixed by the dipper, their wavelength becomes shorter.
  4. If the wavefronts meet the boundary at an angle, the part of each wavefront that reaches the shallow water first slows down first, so the wavefront swings round and changes direction.
  5. This change of direction caused by a change of speed is refraction, the same effect that bends light at the surface of a glass block.
Practical

Investigating refraction of ripples

  • Aim: to observe how ripples change speed, wavelength and direction when they pass from deep water into shallow water.
  • Apparatus: a ripple tank, water, a straight dipper and motor, a lamp, a white screen, a rectangular sheet of clear plastic about 5 mm5\ \text{mm}5 mm thick, a stroboscope or camera, a metre ruler and a protractor.
  • Method:
    • Lay the plastic sheet in one half of the tank and add water until it covers the sheet by about 1 mm1\ \text{mm}1 mm, giving a deep region and a shallow region.
    • Set the dipper running so that straight wavefronts travel towards the edge of the sheet, first with the wavefronts parallel to the edge.
    • Freeze the pattern with the stroboscope or a photograph and measure the wavelength in each region across several wavefronts.
    • Turn the sheet so that its edge is at about 45∘45^\circ45∘ to the oncoming wavefronts.
    • Freeze the pattern again, draw the direction of travel on each side of the boundary, and use the protractor to measure how much the direction changes.
  • Results: the wavelength is shorter over the sheet, showing that the ripples slow down in shallow water, and when they arrive at an angle the wavefronts change direction at the boundary.
  • Variables: the depth of water over the sheet and the frequency of the dipper are kept the same, so that any change is caused by the boundary alone.
  • Watch out: if the water over the sheet is too deep the change in speed is too small to see, and if it is too shallow the ripples die away.
  • Safety: use a low-voltage supply for the motor and lamp, and keep mains plugs well away from the tank.
Example

Speed of sound from an echo

  • A student stands 85 m85\ \text{m}85 m from a tall brick wall and claps once.
  • The echo is heard 0.50 s0.50\ \text{s}0.50 s after the clap.
  • The sound travels to the wall and back, so the total distance is twice the distance to the wall.
d=2×85=170 m d = 2 \times 85 = 170\ \text{m} d=2×85=170 m v=dt=1700.50=340 m/s v = \frac{d}{t} = \frac{170}{0.50} = 340\ \text{m/s} v=td​=0.50170​=340 m/s
Common Mistake
  • Do not describe a ripple as a wave that travels up and down, because the ripple travels across the water while the surface moves up and down.
  • Do not forget to double the distance in an echo method, because the sound travels to the wall and back again.
Exam technique

Describing a speed measurement

  • State the two quantities you measure, a distance and a time, and name the equipment for each.
  • Say how you make the timing accurate, such as slow-motion video for ripples or microphones and an electronic timer for sound.
  • Mention repeating the measurement and calculating a mean.
  • Finish with the equation you use to calculate the speed.
Self review
  • Why are ripples on water used as a model of transverse waves?
  • How do air particles move as a sound wave passes through them?
  • Why can a hand-held stopwatch not be used to time sound over a distance of 1 m1\ \text{m}1 m?
  • What happens to the wavelength of ripples as they pass into shallower water?
  • Why is the distance doubled when an echo is used to measure the speed of sound?

5.1.11 Evidence that the wave travels, not the medium

The wave travels, not the medium

Definition

Wave

A travelling disturbance that transfers energy from one place to another without transferring matter.

Definition

Medium

The substance, such as air, water or steel, through which a wave travels.

  1. A wave transfers energy from one place to another, but the medium it travels through does not travel with it.
  2. Each particle of the medium oscillates about its rest position and passes the disturbance on to the next particle.
  3. Once the wave has passed, every particle is back where it started, so there is no overall movement of the material.
  4. A Mexican wave at a football ground works in the same way, because the wave races round the stadium while each fan only stands up and sits down in their own seat.
  5. Water particles and air particles are far too small to watch, so the evidence comes from objects that move along with them.

Evidence from water ripples

  1. A cork, a leaf or a small piece of paper floating on water moves exactly as the surface beneath it moves.
  2. As ripples pass, the floating object bobs up and down, with a slight back-and-forth movement.
  3. The floating object is not carried along with the ripples, and once they have passed it is still in about the same place.
  4. If the water itself travelled with the ripples, the floating object would be swept across to the far side.
  5. A duck sitting on a pond rises and falls as ripples from a thrown stone pass beneath it, but it does not drift towards the bank.
  6. This shows that the ripple, and the energy it carries, travels across the water while the water stays where it is.
Practical

A floating cork in a ripple tank

  • Aim: to show that ripples travel across the water while the water itself stays in place.
  • Apparatus: a ripple tank or large shallow tray of water, a dipper and motor or a pencil to tap the surface, a small cork or a few pieces of paper confetti, a ruler fixed to the side of the tank and a mobile phone to film from the side.
  • Method:
    • Let the water settle completely, then place the cork gently near the middle of the tank.
    • Note the cork's starting position against the ruler on the side of the tank.
    • Start the dipper, or tap the surface steadily at one end, so that a train of ripples travels past the cork.
    • Film the cork from the side so that you can watch both the ripples and the cork.
    • Stop the ripples and compare the cork's final position with its starting position.
  • Results: the ripples travel the full length of the tank, but the cork only rises and falls with a small back-and-forth motion and ends up in almost the same place.
  • Conclusion: the energy of the wave travels across the tank, but the water does not.
  • Watch out: a draught or a tilted tank can make the cork drift for reasons that have nothing to do with the ripples, so close the windows and check the tank is level.
  • Safety: keep electrical equipment away from the water and mop up any spills straight away.

Evidence from sound in air

  1. Air particles are invisible, so the evidence comes from the effect sound has on something light that sits in the air.
  2. A candle flame placed in front of a loudspeaker playing a loud, low note flickers backwards and forwards, but it is not blown away from the speaker.
  3. The flame moves back and forth because the air around it vibrates back and forth as compressions and rarefactions pass through it.
  4. If the air were flowing away from the loudspeaker, the flame would lean steadily away from it, as it does in a draught.
  5. Wind is a flow of air from one place to another, while a sound wave is a vibration of air in place, which is why loud music does not blow your hair back.
  6. A ribbon tied to a stretched slinky shows the same thing for any longitudinal wave, because it moves back and forth as compressions pass but stays at the same point on the spring.
Practical

A candle flame by a loudspeaker

  • Aim: to show that a sound wave travels through the air while the air itself only vibrates back and forth.
  • Apparatus: a loudspeaker, a signal generator, a candle in a stable holder on a heatproof mat, and matches or a lighter.
  • Method:
    • Place the lit candle about 5 cm5\ \text{cm}5 cm in front of the loudspeaker cone, in a room with no draughts.
    • Connect the loudspeaker to the signal generator and set a low frequency of about 20 Hz20\ \text{Hz}20 Hz to 50 Hz50\ \text{Hz}50 Hz.
    • Turn up the amplitude slowly until the sound is clearly audible, and watch the flame closely or film it in slow motion.
    • Switch off the signal generator and compare the flame with how it looked before.
  • Results: the flame flickers rapidly towards and away from the speaker, but it does not lean steadily away or blow out.
  • Conclusion: the air near the speaker vibrates about a fixed position as the sound passes, so the sound wave travels but the air does not flow.
  • Watch out: at high frequencies the flickering is too fast to see, so keep the frequency low.
  • Safety: tie back long hair, keep the candle on a heatproof mat away from paper, and never leave the flame unattended.
Common Mistake
  • Do not say that the particles of the medium stay completely still, because they do move, but only back and forth about their rest positions.
  • Do not confuse a sound wave with wind, because wind carries air from place to place while sound does not.
Exam technique

Describing the evidence

  • For each type of wave, give an observation followed by the conclusion you draw from it.
  • Name the object you watch, such as a cork on water or a candle flame near a loudspeaker.
  • Describe its motion precisely, as up and down or back and forth about a fixed position.
  • Finish by stating that the wave, and the energy it carries, travels while the water or air does not.
Self review
  • What does a wave transfer from one place to another?
  • How does a cork on water move as ripples pass it?
  • What does the motion of the cork show about the water?
  • Why does a candle flame flicker in front of a loudspeaker instead of being blown away?
  • What is the difference between the movement of air in wind and in a sound wave?

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Labelled comparison of a transverse wave and a longitudinal wave showing amplitude, wavelength, crest, trough, compression, rarefaction, and the directions of wave travel and particle vibration

A wave is a travelling disturbance that transfers energy from one place to another. In most mechanical waves, the particles of the medium only vibrate about their rest positions, so the material is not carried along with the wave.

Amplitude is the maximum displacement from the rest position, and a larger amplitude usually means more energy is transferred. Wavelength, symbol λ\lambdaλ, is the distance between matching points such as crest to crest or compression to compression.

Frequency, symbol fff, is the number of complete waves each second and is measured in hertz. Period, symbol TTT, is the time for one complete wave, and wave speed, symbol vvv, tells you how fast the wave pattern travels and is measured in m s−1\text{m s}^{-1}m s−1.

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A student moves one end of a long rope up and down. A wave travels along the rope.

The Figure shows the shape of the rope at one instant.

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What two things can waves transfer between two points without transferring matter?

5.1 Wave behaviour Revision Guide

  1. GCSE
  2. /Physics
  3. /5.1 Wave behaviour

Revision notes for OCR GCSE Physics 5.1 Wave behaviour: explanations and worked examples on 5.1.1 Describing wave motion, 5.1.2 Wavelength and frequency, 5.1.3 Wave speed, frequency and wavelength, 5.1.4 Wave speed problems, 5.1.5 Transverse and longitudinal waves, 5.1.6 Sound waves crossing between media, 5.1.7 Reflection, transmission and absorption at interfaces, 5.1.8 Sound waves and vibrations in solids, 5.1.9 Frequency range and human hearing, 5.1.10 Modelling waves with water ripples and sound, and 5.1.11 Evidence that the wave travels, not the medium.

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