A transformer is used to step down the potential difference (p.d.) of an alternating current supply.
The table below shows the specifications and measurement data for this transformer:
| Parameter | Value |
|---|---|
| Number of turns on the primary coil | 2400 |
| Number of turns on the secondary coil | 150 |
| p.d. across the primary coil | 120 V |
| Current in the secondary coil | 8.0 A |
Calculate the potential difference across the secondary coil of the transformer.
Calculate the current in the primary coil of the transformer, assuming the transformer is 100% efficient.
16 exam-style questions on OCR GCSE Physics Uses of magnetism. Each one has a worked solution and a mark scheme showing where the marks go.